Astronomy Lecture Day 02 Scale, Ratios and Proportions
- Intro
- Collect Extra-credit HW
- Problems or questions
- Today’s goals
- Introduce the structures on the Universe
- Review ratios and proportions to better understand the scale of the Universe
- See the First exam study guide
- Structures of the Universe
- List the principle structures in increasing size
- Moons and Planets
- Stars: The Sun and star fields ( , )
- Planetary Systems
- Star clusters: an open cluster and a globular cluster
Galaxies: The Whirlpool galaxy
- Galaxy Clusters: rich cluster and poor clusters
- Scale Video: Astronomy Picture of the day on 20 Jan 2010: (6 min)
- Bookmark or favorite this web site, check it daily
- Another scale exercise: APOD 12 Mar 2012
- Working with ratios to better understand the scale
- Distance to the Sun compared to the diameter of the Earth
- Distance to Sun is 1 AU = 1.51011 m = 1.5108 km
- How to convert from m to km: divide by 1,000 or reduce the exponent by 3
- How to convert from km to m: multiple by 1,000 or increase the exponent by 3
- The distance between the Sun and Earth (center to center) is equivalent to 12,000 Earth diameters. (Imagine if the Earth was $1!)
- Diameter of the Milky Way compared to the diameter of the Solar System
- Diameter of Milky Way is 100,000 ly = 100,000(9.461015m) = 9.461020 m =9.461017 km
- Diameter of the Solar System is about 80 AU = 80(1.51011 m) = 1201011 m = 120108 km
- The diameter of the Milky Way galaxy is equivalent to about 79 millionSolar System diameters. (Imagine if the Solar System diameter was $1!)
- Distance to Whirlpool Galaxy (M51 or NGC 5194) compared to the diameter of the Milky Way
- Distance to Whirlpool galaxy is about 23 million ly = 23,000,000 ly = 23106 ly =(23106)(9.461015 m) = 2.181023m =2.181020 km
- Diameter of the Milky Way is about 100,000ly =9.461017 km
- The Whirlpool galaxy is about 230Milky Way diameters away.
- Working with proportions to better understand scale
- If the Earth had a diameter of 1 foot, what would be the diameter of the Sun?
- General rule for scale problems solved with proportions:
- Actual #1 = Diameter of the Earth = 26,378 km
- Actual #2 = Diameter of the Sun = 2696,000 km
- Model #1 = 1 foot
- Model #2 = unknown model size of the Sun, x
- , cancel the 2’s, cross multiply and solve for x.
- If the Earth had a diameter of 1 foot, the Sun’s diameter would be about 36 yards. Image a football (1 foot length) on the 36 yard line of a football field.
- If the Earth had a diameter of 1 inch, what would be the distance to the stars in Orion’s Belt?
- Actual #1 = Diameter of the Earth = 26,378 km
- Actual #2 = Distance of stars in Orion’s Belt = 1340 ly = 1340 (9.461015 m) = 1.271019 m = 1.271016 km
- Model #1 = 1 inch
- Model #2 = unknown model distance to stars in Orion’s Belt, x
- , cross multiply and solve for x.
- If the Earth had a diameter of 1 inch, the most distance star in Orion’s Belt would be about 16 million miles away. (16 million miles is 17% of an AU!)
- If the Sun had a diameter of 1 cm, what would be the diameter of the Milky Way?
- Actual #1 = Diameter of the Sun = 2696,000 km
- Actual #2 = Diameter of Milky Way = 100,000 ly = 100,000 (9.461015 m) = 9.461019 m = 9.461016 km
- Model #1 = 1 cm (about ½ an inch)
- Model #2 = unknown model diameter of the Milky Way galaxy, x
- , cross multiply and solve for x.
- If the Sun had a diameter of 1 cm, the Milky Way would have a diameter of 680,000 km. (If the Sun where 1 cm in diameter, the Milky Way would be almost as big as the real Sun!!
- Summary
- Pale Blue Dot image from the Cassini Spacecraft orbiting Saturn: APOD 16 Oct 2006
- Handout the HW, due on Tuesday
- We begin Units 5, 6 & 7 next week. Please look these over.
- Look at Dr. Fred’s Five Rules for the Apparent Motion of the Stars on Hot Tips Week 2