Half-life Practice
#1:The half-life of Zn-71 is 2.4 minutes. If one had 100.0 g at the beginning, how many grams would be left after 7.2 minutes has elapsed?
#2:Pd-100 has a half-life of 3.6 days. If one had 6.02 x 1023atoms at the start, how many atoms would be present after 20.0 days?
#3:Os-182 has a half-life of 21.5 hours. How many grams of a 10.0 gram sample would have decayed after exactly three half-lives?
#4:After 24.0 days, 2.00 milligrams of an original 128.0 milligram sample remain. What is the half-life of the sample?
#5:U-238 has a half-life of 4.46 x 109years. How much U-238 should be present in a sample 2.5 x 109years old, if 2.00 grams was present initially?
#6:How long will it take for a 40.0 gram sample of I-131 (half-life = 8.040 days) to decay to 1/100 its original mass?
#7:Fermium-253 has a half-life of 0.334 seconds. A radioactive sample is considered to be completely decayed after 10 half-lives. How much time will elapse for this sample to be considered gone?
#8:At time zero, there are 10.0 grams of W-187. If the half-life is 23.9 hours, how much will be present at the end of one day? Two days? Seven days?
#9:100.0 grams of an isotope with a half-life of 36.0 hours is present at time zero. How much time will have elapsed when 5.00 grams remains?
#10:How much time will be required for a sample of H-3 to lose 75% of its radioactivity? The half-life of tritium is 12.26 years.
11)Fluorine-21 has a half life of approximately 5 seconds. What fraction of the original nuclei would remain after 1 minute?
12)Iodine-131 has a half life of 8 days. What fraction of the original sample would remain at the end of 32 days?
13)The half-life of chromium-51 is 28 days. If the sample contained 510 grams, how much chromium would remain after 56 days? How much would remain after 1 year? How much was present 168 days ago?
14)If 20.0 g of a radioactive isotope are present at 1:00 PM and 5.0 g remain at 2:00 PM, what is the half life of the isotope?
15)The half life of Uranium-238 is 4.5 billion years and the age of earth is 4.5 X 109 years. What fraction of Uranium-238 that was present when Earth was formed still remains?
16)Chromium-48 decays. After 6 half-lives, what fraction of the original nuclei would remain?
17)The half life of iodine-125 is 60 days. What fraction of iodine-125 nuclides would be left after 360 days?
18)Titanium-51 decays with a half life of 6 minutes. What fraction of titanium would remain after one hour?
19)A medical institution requests 1 g of bismuth-214, which has a half life of 20 min. How many grams of bismuth-214 must be prepared if the shipping time is 2 h?
20)The half life of radium 226 is 1602 years. If you have 500 grams of radium today how many grams would have been present 9612 years ago?
Answers
#1
7.2 / 2.4 = 3 half-lives
(1/2)3= 0.125 (the amount remaining after 3 half-lives)
100.0 g x 0.125 = 12.5 g remaining
#2
20.0 / 3.6 = 5.56 half-lives
(1/2)5.56= 0.0213 (the decimal fraction remaining after 5.56 half-lives)
(6.02 x 1023) (0.0213) = 1.28 x 1022atoms remain
#3
(1/2)3= 0.125 (the amount remaining after 3 half-lives)
10.0 g x 0.125 = 1.25 g remain
10.0 g - 1.25 g = 8.75 g have decayed
Note that the length of the half-life played no role in this calculation. In addition, note that the question asked for the amount that decayed, not the amount that remaining.
#4
2.00 mg / 128.0 mg = 0.015625
How many half-lives must have elapsed to get to 0.015625 remaining?
(1/2)n= 0.015625
n log 0.5 = log 0.015625
n = log 0.5 / log 0.015625
n = 6
24 days / 6 half-lives = 4.00 days (the length of the half-life)
#5
(2.5 x 109) / (4.46 x 109) = 0.560 (the number of half-lives that have elapsed)
(1/2)0.560= 0.678 (the decimal fraction of U-238 remaining)
2.00 g x 0.678 = 1.36 g remain
#6
(1/2)n= 0.01
n log 0.5 = log 0.01
n = 6.64
6.64 x 8.040 days = 53.4 days
#7
0.334 x 10 = 3.34 seconds
#8
24.0 hr / 23.9 hr/half-life = 1.0042 half-lives
One day = one half-life; (1/2)1.0042= 0.4985465 remaining = 4.98 g
Two days = two half-lives; (1/2)2.0084= 0.2485486 remaining = 2.48 g
Seven days = 7 half-lives; (1/2)7.0294= 0.0076549 remaining = 0.0765 g
#9:
5.00 / 100.0 = 0.05 (decimal fraction remaining)
(1/2)n= 0.05
n log 0.5 = log 0.05
n = 4.32 half-lives
36.0 hours x 4.32 = 155.6 hours
#10
If you lose 75%, then 25% remains. Use 0.25 rather than 25%.
(1/2)n= 0.25
n = 2 (remember (1/2)2= 1/4 and 1/4 = 0.25)
12.26 x 2 = 24.52 years
Comment: the more general explanation follows:
(1/2)n= 0.25
n log 0.5 = log 0.25
n = log 0.25 / log 0.5
n = 2
11)Fluorine-21 has a half life of approximately 5 seconds. What fraction of the original nuclei would remain after 1 minute?
- The answer is solved by creating the fraction . Where n = the
- number of half lives. If each half life is 5 seconds, then in one minute
- (60 seconds) there are 12 half lives. Therefore the answer is:
12)Iodine-131 has a half life of 8 days. What fraction of the original sample would remain at the end of 32 days?
- Using the same fraction, you must figure out n. If the half life is 8 days,
- then in 32 days, there are 4 half lives. Therefore the answer is:
13)The half-life of chromium-51 is 28 days. If the sample contained 510 grams, how much chromium would remain after 56 days? How much would remain after 1 year? How much was present 168 days ago?
- In this problem, the fraction will be multiplied by the initial amount.
- In the first problem each half life is 28 days, therefore in 56 days two half lives occur. This means that n=2. The solution is as follows:
- The second is solved the same way except that there are 13 half lives
- over one year. This means n=13. The solution is as follows:
- The third is solved by recognizing there must be more of the
- sample 168 days ago then there is now. 168 days represents
- 3 half lives so n=3. The solution is:
14)If 20.0 g of a radioactive isotope are present at 1:00 PM and 5.0 g remain at 2:00 PM, what is the half life of the isotope?
- In this problem, you must figure out how many half lives have occurred.
- After one half life 20.0g becomes 10.0g. After a second half life, 10.0g becomes 5.0g. This means that during the question, two half lives have occurred. Since this happened over the course of 1 hour, then each half life must be equal to:
- 30 minutes.
15)The half life of Uranium-238 is 4.5 billion years and the age of earth is 4.5 X 109 years. What fraction of Uranium-238 that was present when Earth was formed still remains?
- 4.5 billion is exactly the same as 4.5 x 109. Therefore, the age of the
- Earth is equal to one half life of Uranium. This means that n=1. The solution is a follows:
16)Chromium-48 decays. After 6 half-lives, what fraction of the original nuclei would remain?
- The answer is solved by creating the fraction . Where n = the
- number of half lives. If there are 6 half lives, then n=6.Therefore the
- answer is:
17)The half life of iodine-125 is 60 days. What fraction of iodine-125 nuclides would be left after 360 days?
- The answer is solved by creating the fraction . Where n = the
- number of half lives. If each half life is 60 days, then in 360 days
- there are 6 half lives. Therefore the answer is:
18)Titanium-51 decays with a half life of 6 minutes. What fraction of titanium would remain after one hour?
- The answer is solved by creating the fraction . Where n = the
- number of half lives. If each half life is 6 minutes, then in 1 hour (60
- minutes) there are 10 half lives. Therefore the answer is:
19)A medical institution requests 1 g of bismuth-214, which has a half life of 20 min. How many grams of bismuth-214 must be prepared if the shipping time is 2 h?
- In this problem you must figure out the initial amount. If you use the
- same set up as question 3, then you can solve for the initial amount. You
- just have to figure out n. If each half life is 20 minutes, and 2 hours (120
- minutes) go by, then n=6. The set up is as follows:
- Solving for x, x = 64g.
20)The half life of radium 226 is 1602 years. What fraction of a sample radium-226 would remain after 9612 years?
- If each half life is 1602 years, then in 9612 years
- there are 6 half lives. Therefore the answer is: