Abstract:

By tracing rays as they are affected through convex or concave mirrors and lenses and a plano-convex lens, we attempt to find various things such as the index of refraction, the focal point and radius which are specific for the certain lenses and mirrors used.

Data: (See Excel Spreadsheet) Next time insert data in the word document.

Graphs: (Attached at the end)

Sample Calculations/Results:

1.  a. Θi = 17.0°

b. Θr = 17.0°

2. R = 2f

R = 2fconvex lens

R = 6.6675 x 10-2m

3. R = 2f

R = 2fconcave mirror

R = 7.0 x 10-2m

Dconcave mirror = 1.4 x 10-1m

4. Ri = 9.3 x 10-2m Rr = 9.3 x 10-2m f = 1.42875 x 10-1m

1 / f = ( n - 1 ) [ ( 1 / Ri ) + ( 1 / Rr ) ]

n = 1.325459318

5. R = 2fconcave lens

R = 6.5 x 10-2m

6. Θcritical =132.0°

% Error:

In this lab we did not obtain a percent error. Both our angles of incidence and reflection were equal to each other as we had expected.

Questions:

1. 

·  Two uses for Convex Mirrors: Hospital Corner Mirrors, rear/side view mirrors

·  Two uses for Concave Mirrors: Microscopes Make up mirrors.

2. 

3.  We predict that one would see a virtual image of the world above the surface of the pool because of the surface tension of the water. That tension would cause a very large meniscus, which for our purposes is like a convex lens.

Conclusion:

In this experiment we were to trace rays as they were affected through convex or concave mirrors and lenses and a plano-convex lens. We attempted to find various things such as the index of refraction, the focal point and radius which are specific for the certain lenses and mirrors used. For the flat mirror we found out that the angle of incidence was equal to the angle of refraction with the use of a protractor. We also found the focal point and radius of curvature of the convex mirror. We also found the radius of curvature of the concave mirror. After this we found the focal length of the concave lens. Finally we found the critical angle of the plano-convex lens with the use of a protractor. After doing our calculations we found that we had no percent error. This is due to the fact that our angle of incidence in the flat mirror was equal to the angle of reflection. The reason for this result is the fact that our graphs were very accurately drawn allowing for such results.

98/100