MTH 157 – Math For Elementary Teachers II

Week #6 Chapter 11 - 12 Cumulative Test

Name:

Score: x/100

Please show your work or justify your answer. Work or justification must be shown for full credit.

Use the equation editor to show fractions and special symbols.

All questions are worth 5 points. Your grade is your percentage score.

1. Identify the motion or combination of motions that would produce the image.
Instructor’s comments
2. Describe all symmetries of the figure shown.
Instructor’s comments
3. Describe the symmetries of the object:
Instructor’s comments
4. The slide arrow and line of reflection of a glide reflection are given. Find the point of the grid (Q, R, S, or T) that is the same as the image P'' of the point P under two successive glide reflections.
Instructor’s comments
5. Can a tessellation be drawn using the following figure? Draw it on paper to check. You need not show your tessellation here.
Instructor’s comments
6. Will any kite tessellate the plane?
Explain.
Instructor’s comments
7. A vertex arrangement can be listed by listing the number of sides of each polygon surrounding the vertex. For example, an arrangement of a square, a triangle, a parallelogram and a triangle can be shown as 4, 3, 4, 3. List the vertex arrangements for the following tessellation.
Instructor’s comments
8. Describe the figure or polygon produced by interpreting the symbol .
Instructor’s comments
9. What is the measure of the dent angle for a star-shaped polygon with 4 points and a point angle of 40°?
Instructor’s comments
10. Decide whether the figure shown is a polyhedron.
Explain
Yes, the figure shown is that of a polyhedron because it is a closed figure bounded by polygonal faces.
Instructor’s comments
11. A polyhedron has 33 edges and 20 faces. How many vertices does it have?
V + F = E + 2
V = E + 2 - F = 33 + 2 - 20 = 15
It has 15 vertices
Instructor’s comments
12. A right circular cylinder has a radius of 2 inches. Its volume is 40 in2. If the radius is doubled, what is the new volume?
V1/V2 = (R1/R2)^2
V2 = V1 * (R2/R1)^2 = 40 * (2^2) = 160 in^2
Instructor’s comments
13. Convert the units:
11 kg = mg
11 kg = 11 kg * 1000000 mg/1 kg = 11000000 mg
Instructor’s comments
14. Make the following conversion to the nearest degree:
– 19º F = º C
° C = (° F - 32) * (5/9) = (-19 - 32) * (5/9) = -28
Instructor’s comments
15. A 2200 g bag of sugar was on sale for $0.94. How much would you have to pay for 33 kg of sugar?
2.2 kg costs $0.94
\ 33 kg costs (33/2.2) * 0.94 = $14.10
Instructor’s comments
16. Find the perimeter:
Perimeter = Sum of all sides of the trapezoid = 12 + 23 + 12 + 29 = 76 m
Instructor’s comments
17. A flower garden extends from the corner of a house in a three-quarter circle. The radius of the flower bed is 2.5 ft. If the edging material costs $0.45 per linear foot, what is the cost of edging the entire bed (not including the portion against the house). Round your answer to the nearest cent.
The length to be edged = (3/4) * circumference = (3/4) * 2p (2.5) = 11.781 ft
Cost of edging = 11.781 * 0.45 = $5.30
Instructor’s comments
18. Find the area of the figure.
Area = 2 * area of the square with side 83 m + area of the parallelogram
= 2 * 83^2 + 83 * 62.25 = 18944.75 m^2
Instructor’s comments
19. Find the surface area of the solid.
Right circular cylinder with r = 7 cm, h = 5 cm
Total surface area = 2p r (r + h) = 2p (7)(7 + 5) = 527.79 cm^2
Instructor’s comments
20. Solve. Use 3.14 as an approximation for π.
An aluminum cylindrical juice can has a height of 10 in. and a radius of 6 in. How many square inches of aluminum are needed to make the can? Round to one decimal place.
Assuming a closed can, Total surface area = 2p r (r + h) = 2p (6)(6 + 10) = 603.2 in^2
Thus, 603.2 in^2 of aluminum is needed to make the can.
Instructor’s comments
Correct and complete answer, all work is shown and is Correct. / Full credit
Full and complete answer, some minor errors or omissions in work / Partial credit
Minor errors* in answer or partial answer. Work is complete and correct except for these errors in the final answer / Partial credit
Incorrect or incomplete answer with no work shown or major errors in work / No credit

* A minor error is defined as a small mistake that may affect the results, but does not reflect misunderstanding or misapplication of the concepts. An example would be a missing sign in a step, when it had been present in previous steps. Incorrect digits and rounding errors are not considered minor.

MTH 157 Week #6 Cumulative Test