Quantitative Methods Quiz #2
Forecasting & Regression Analysis
3 MA Error 3 WMA Error
1. SalesForecast[Sales – Forecast]Forecast[Sales – Forecast]
Jan 64 -- --
Feb 70 -- --
Mar 68 -- --
Apr 64 67.333.33 68.204.20
May 72 67.333.33 65.806.20
Jun 71 68.003.00 69.201.80
July ? 69.00 70.60
Calculate the 3 month Moving Average for July, the 3 month Weighted Moving Average for July using weights of .60, .30, .10. Then use the date to estimate the MAD for each. Explain which is a better forecasting model?
3 MAMAD = (3.33+3.33+3.00)/3 = 3.22
3 WMAMAD = (4.20+6.20+1.80)/3 = 4.67
From the results of the MAD test we can see that the 3 MA model is a more accurate model for forecasting sales. The 3 MA had a MAD of 3.22 while the 3 WMA had a MAD of 4.67. Since the 3 MA is lower, it is more accurate.
2. n = 10 X = 55 Y = 207 X = 385 XY = 1228
- Use the above data to calculate the regression line Y = a + bX.
- If X = 12, what is the estimate for Y?
- If the Coefficient of Determination is 0.935 , explain what this means.
1228 – 10(5.5)(207)89.5
A. b = ------= 1.085
385 – 10(5.5) 82.5
a = 20.7 – 1.085(5.5) = 15.02Y = 15.02 + 1.085 X
B.Y = 15.02 + 1.085 (12) = 28.04
C. The Coefficient of Determination tells me the reliability of the regression line. Since it is 0.935, this means the resulting forecast is very reliable.
3. SalesForecast[Sales – Forecast]alpha x [Sales – Forecast]
Sept 41
Oct 42 411.000.40
Nov37 42.40 -5.40 -1.16
Dec33 35.84 -2.84 -1.14
Jan ? 31.86
Using an alpha constant = .40 , use Exponential Smoothing to Forecast sales for January.
4.Y = $90.00 + $48.50 X + $0.40 X Coefficient of Correlation = 0.68
Y = travel cost X = days on the road X = distance in miles traveled
A If Zhou Shan was on a business trip for 5 days and traveled 300 miles, what is the expected travel cost?
- Zhou submitted a request for reimbursement for $600, should it be paid? Why or Why not? Is this a valid model?
- Y = 90.00 + 48.50(5) + 0.40(300)
Y = 452.50
B. Based on the calculations, Zhou’s request appears to be a little high. But because the Coefficient of Correlation is only 0.68, it is not very reliable. So we should pay the request until we find a more accurate model. The model is NOT valid.