Exploration of Space Lecture B

In the previous lesson, we saw the great contributions the Kepler made to the understanding of how planets and other objects move around the sun. Kepler realized that the sun somehow controlled the motion of the planets, but he was unable to explain how it did this. It was left to Newton, fifty years later, to provide a satisfactory answer. In this lesson we will see how Newton developed his Law of Universal Gravitation.

Newton graduated from Cambridge University in 1665 after majoring in mathematics. In the few years after this, Newton did some of his best thinking. Legend has it that while watching an apple fall, Newton began to wonder if the force that accelerated the fall of the apple might also be the one responsible for maintaining the path of the moon’s orbit. The moon is moving around Earth in a circular orbit and thus has centripetal acceleration. This acceleration is caused by the gravitational pull between the moon and Earth. The amount of this acceleration due to gravity was proportional to the gravitational force between Earth and the moon. By using his knowledge of circular motion and Kepler’s Third Law, Newton deduced that the gravitational force was inversely proportional to the square of the distance from Earth to the moon.

Newton’s reasoning was similar to the following. From our work on circular motion, we know that the centripetal force required to keep an object moving in a circle is

From Kepler’s Law,

By substituting this value for T2 into the equation for force, we obtain

Since the expression (4p2K) is a constant, the force of gravitational attraction on a planet is directly proportional to the mass of the planet and inversely proportional to the square of its distance from the sun. We saw in the previous lesson that Kepler’s constant is the same for any object circling the sun, but it would have a different and smaller value for a satellite of Earth. Newton reasoned that this is because the mass of Earth is smaller than the mass of the sun. In other words, Kepler’s constant is proportional to the mass of the object exerting the force of attraction at the centre of the orbit. So the expression 4p2K is proportional to mc where mc refers to the mass of the central body (like the sun or Earth). We can thus rewrite this expression as 4p2K = G mc. The value G is referred to as a universal gravitational constant. Henry Cavendish first experimentally measured it in 1798. Newton’s remarkable extension was to say that if this equation for force applies to the sun and its planets, and to Earth and its moon, then it should apply to any body in the universe that has mass. We can summarize Newton’s Law of Universal Gravitation as

Any two bodies attract each other with forces proportional to the mass of each and inversely proportional to the square of the distance between them.

where G = 6.67 x 10-11 Nm2/kg2

Example

Two basketballs of mass 0.65 kg are placed 1.0 m apart. What is the force of gravitational attraction between them?

Solution

F = (6.67 x 10-11 Nm2/kg2)(0.65 kg)(0.65 kg)/(1.0)2 = 2.8 x 10-11 N

Example

The moon has a mass of 7.34 x 1022 kg and the mass of the earth is 5.98 x 1024 kg. The force of gravitational attraction between the moon and the earth is 2.00 x 1020 N. What must be the distance between the moon and the earth?

Solution

Example

Proportional reasoning:

Two objects of identical mass are found to attract each other with a gravitational force of 10 N. What happens to this 10 N if:

a)  the mass of one of the objects is doubled

b)  both the masses are doubled

c)  the distance between them is doubled

d)  the mass of one of the objects is doubled and the distance between them is doubled

Solution

Look at the formula to guide your thinking.

a)  the force will be multiplied by two (2 x 10 N = 20 N)

b)  the force will be multiplied by four (4 x 10 N = 40 N)

c)  think of it as 1/R2, and R = 2. Therefore the force will be multiplied by ¼ (1/4 x 10 N = 2.5 N)

d)  the force will be multiplied first by 2, but then multiplied by ¼ (2 x 10 N x ¼ = 5 N)