Graded AssignmentSCI203A: Biology |Unit 3 | Lessons10 and 11: Laboratory: Determining the Rate of Diffusion
Name: / Date:Graded Assignment
Lab Report
Answer the questions below. When you are finished, submit this assignment to your teacher by the due date for full credit.
Completing Data Tables
(5 points)
Score- Look at the sample cube and example data table. Then complete the data tables based on your observations during Parts A and B of the lab.
Sample Cube
Example Data Table: Calculations for Sample Cube
Surface Area (SA) / Sides / Length / Width / SA for Sample Cube6 / 4 / 4 / 6 x 4 x 4 = 96
Volume (V) / Length / Width / Height / V for Sample Cube
4 / 4 / 4 / 4 x 4 x 4 = 64
Surface Area-to-Volume Ratio (SA/V) / SA / V / SA/V for Sample Cube
96 / 64 / 96/64 = 1.5
Answer:
Data Table 1: Calculations for Cube 1
Surface Area (SA) / Sides / Length / Width / SA for Cube 16 / 1cm / 1cm / 6x1x1=6
Volume (V) / Length / Width / Height / V for Cube 1
1cm / 1cm / 1cm / 1x1x1=1
Surface Area-to-Volume Ratio (SA/V) / SA / V / SA/V for Cube 1
6cm / 1cm / 6÷1=6
Data Table 2: Calculations for Cube 2
Surface Area (SA) / Sides / Length / Width / SA for Cube 26 / 2cm / 2cm / 6x2x2=24
Volume (V) / Length / Width / Height / V for Cube 2
2cm / 2cm / 2cm / 2x2x2=8
Surface Area-to-Volume Ratio (SA/V) / SA / V / SA/V for Cube 2
24 / 8 / 24÷8=3
Data Table 3: Calculations for Cube 3
Surface Area (SA) / Sides / Length / Width / SA for Cube 36 / 2.5cm / 2.5cm / 6x2.5x2.5=37.5
Volume (V) / Length / Width / Height / V for Cube 3
2.5cm / 2.5cm / 2.5cm / 2.5x2.5x2.5=15.625
Surface Area-to-Volume Ratio (SA/V) / SA / V / SA/V for Cube 3
37.5 / 15.625 / 37.5÷15.625=2.4cm
Data Table 4: Diffusion Rates
Length of Side / Part A: 5 MinutesStart Time:
Finish Time: / Part B: 10 Minutes
Start Time:
Finish Time:
Distance Vinegar Diffused / Diffusion Rate
(mm/minute) / Distance Vinegar Diffused / Diffusion Rate
(mm/minute)
1 cm / 2mm / 2÷5=0.4mm/min / 10mm / 10÷10=1mm/min
2 cm / 3mm / 3÷5=0.6mm/min / 4.5mm / 4.5÷10=0.45mm/min
2.5 cm / 2.5mm / 2.5÷5=5mm/min / 3mm / 3÷10=0.3mm/min
Analysis Questions
(4 points)
Score- Look at your data tables. List the cubes in order from largest to smallest. Then list them again in order of the surface area-to-volume ratios, from the largest ratio to the smallest ratio. Compare the lists.
Answer:
Making Graphs
(2points)
Score- Make a graph of your data, showing the distance vinegar diffused versus the surface area-to-volume ratio. Your graph should plot distance on the vertical axis, and the ratio on the horizontal axis. Plot the points on your graph and connect them with a line.
Answer:
(2points)
Score- Make another graph, this time showing the diffusion rate (mm/minute) versus surface area-to-volume ratio. Plot the rate on the vertical axis, and the ratio on the horizontal axis.
Answer:
(2 points)
Score- Observe the two graphs you made, and analyze these results. What does the data tell you about connection between the surface area-to-volume ratio and the diffusion rate?
Answer:
( 8 points)
Score- Did the vinegar diffuse all the way to the center of any of the cubes? If so, which ones? What does this tell you about surface area-to-volume ratio and the diffusion rate? Please use the data from the “Diffusion Rate” data table to support your answer.
Answer:
Concluding Statement
(2 points)
Score- Using what you have learned in this exercise, write a paragraph applying the concepts. Describe a cell which effectively uses diffusion as a means to move materials in and out. Use this information to suggest how being small helps cells survive, and being made of many small cells helps large organisms maintain homeostasis.
Answer:
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