Name______Date______Period______
Equilibrium Notes
Ammonia Gas Production Equilibrium
N2(g)+ 3H2(g) 2NH3(g)
Not equal concentration totals, but the number of NH3 decomposition is equal to the number of NH3 creation.
Opposing processes are in balance:
Forward rate (right) equals backwards rate (left)
How much is actually produced given a reversible reaction at equilibrium is given by:
aA(g) +bB(g) cC(g) + dD(g)
Homogeneous Reactions: all the reactants and products are in the same physical state. When the state is gaseous when there is a pressure increase the equilibrium shifts towards the side (reactant or product) that has the fewest moles – more moles more volume at STP.
Factor which affects only heterogeneous reactions (more than one phase)
Surface area -when 2 different phases react, reaction can only take place on surface. As shown by the flask of ethanol shown . The rates of condensation equals that of evaporation. Keq =[C2H5OH]
- increase surface area by cutting solid into smaller pieces (liquids in smaller droplets)
If a substance is in liquid form assume concentration equals 1 because it is a pure substance, its concentration is constant at a given temperature. Also the same for solids which has a uniform density and thereby concentration remains constant. Thusly these are not included in equilibrium calculations.
- In general - reactants with solids are slow (except powdered)
- gaseous reactants are faster (but watch for diatomic bonds!)
- reactants in ionic solution. are fastest if no bonds to break
Example: Precipitation reaction Ag+(aq) + Cl-(aq) AgCl (s)
(aqueous ions are mobile (unlike in a solid ) and more concentrated than molecules in a gas)
Equilibrium
- Definition: Rate of forward reaction = Rate of reverse reaction
- Writing Keq’s:
a) products in NUMERATOR,
reactants in DENOMINATOR
b) use [ ] around substances and include their phases
c) (+) signs separating substances in equation BECOME (x) signs
d) coefficients BECOME exponents
e) NO liquids or solids !!!!!! Only aqueous and gas
- Solving for Keq’s: put the ENTIRE numerator in ( )
and the ENTIRE denominator in ( )
- Interpreting the equilibrium constant
- If the Keq= >1 then PRODUCTS are favored More products than reactants at equilibrium.
- If Keq near one= significant amounts of both reactants and products
- If Keq= <1 the reactants favored More reactants than products at equilibrium.
LeChatelier: If stressed, shift to relieve stress
1)[ ] as a stress; If increase [ ] of reactants then shift RIGHT to use them up
If decrease [ ] reactants shift LEFT to put them Back
Same idea for products
2)If temp increases shift AWAY from heat
If temp decreases shift TOWARD heat
3)Pressure: Only directly affects gases (indirectly it can affect [ ] of other substances)
If pressure increase shift to side with LESS moles of gases
If pressure decreases, shift to side with GREATER moles of gases
Equilibrium Practice Problems
For the reaction: SiH4(g) + O2(g) SiO2(g) + H2O(g)
a. Write the equilibrium equation:
c. What is the equilibrium constant
if [SiH4] = 0.45M; [O2] = 0.25M; [SiO2] = 0.15M; and [H2O] = 0.10M at equilibrium?
- Which direction would the reaction go and why? (Towards products or reactants?)
2A(g) + B(s) ↔ C(g)
1. For the reaction above, predict which way the reaction will shift: left, right, or none:
a. the concentration of B is increased ______
b. the amount of C is decreased ______
c. the amount of A is decreased ______
2. For the reaction below, what would speed up the reaction?
NH4+ + H2O ↔ NH3 + H3O+
a. the forward reaction
b. the reverse reaction
3. Define reversible reaction equilibrium:
4. An equilibrium shift to the right means:
a. more products are produced
b. more reactants are produced
c. nothing happens
5. Use this reaction for each of the following:
2NO2 (g) + O2 (g) ↔ 2NO3 (g)
a. Write the expression for the equilibriumconstant.
b. If gas concentrations are as follows, 2.10 M NO2, 1.75 M O2, and 1.00 M NO3, calculateKeq
c. Using Keq from part c, are the reactants or products favored?
d. Using Keq from part c, calculate [NO3] if [NO2] = [O2] = 4.3 x 10-6
POTENTIAL ENERGY diagrams
Endo: 1. graph ends high
2. A + B + heat AB
3. H = (+)
Exo 1. graph ends low
2. A + B AB + heat
3. H = (-)