Study Guide Percent Yield

Name

Study Guide Percent Yield

To solve these you must first solve for the amount of the product that is produced. This is a three-step problem and the answer is the calculated yield. To get the percent yield you must divide the actual yield, by the theoretical yield times 100.

1. What is the percent yield when 5.22g of O2 reacts with H2 to produce 3.00 grams of water.

2H2 + O2 à 2H2O

2. What is the percent yield when 4.68g of Fe reacts with S to produce 2.88g of FeS.

Fe + S à FeS

3. What is the percent yield when 5.87g of Mg(OH)2 reacts with HCl to form 12.84g of MgCl2 and water.

Mg(OH)2 + 2HCl à MgCl2 + 2H2O

4. What is the percent yield when 6.25g of AgNO3 reacts with NaCl to form NaNO3 and 4.12g of AgCl.

AgNO3 + NaCl à NaNO3 + AgCl

5. What is the percent yield when 7.81g of HCl reacts with NaOH to produce 5.24g of NaCl and H2O.

HCl + NaOH à NaCl + H2O

6. What is the percent yield when 6.33g of H2SO4 reacts with NaOH to produce 5.92g of Na2SO4 and water.

H2SO4 + 2NaOH à Na2SO4 + 2H2O

7. What is the percent yield when 43.25g of CaC2 reacts with water to produce 33.71g of Ca(OH)2 and C2H2.

CaC2 + 2H2O à Ca(OH)2 + C2H2

8. What is the percent yield when 65.14g of CaCl2 reacts with Na2CO3 to produce 74.68g of CaCO3 and NaCl.

CaCl2 + Na2CO3 à CaCO3 + 2NaCl

9. What is the percent yield when 4.687g of SF4 reacts with I2O5 to produce 6.281g of IF5 and SO2.

5SF4 + 2I2O5 à 4IF5 + 5SO2

Question 1 Solved

1) 5.22 g x 1 mole O2 = 0.163125 mole O2

32.00 g

2) 0.1631 mole O2 x 2 moles H2O = 0.32625 moles H2O

1 mole O2

3) 0.32625 moles H2O x 18 g = 5.8725 grams H2O

1 mole H2O theoretical yield

Percent Yield = Actual yield x 100

Calculated yield

3.00 grams H2O x 100 = 51.09 %

5.8725 grams H2O