Organic Chemistry Revision Assignment 3

(Till Hydroxy Compounds)

1.Draw the organic products formed when compound Z is treated with the following:

Z

(a)PCl5(b)Br2 water

(c)Warm alkaline aqueous I2(d)Hot acidified K2Cr2O7

(e)Hot acidified KMnO4(f)CH3CH2COOH [8 m]

1

(a)
/ (b)

or

(c)
/ (d)

(e)
/ (f)

[ 1 m each]

2.Describe a simple chemical test that you could use to distinguish the following pairs of

compounds. You are to include reagents and conditions, observations and balanced equation(s) in each case. [6 m]

(a) /
P /
Q

Reagents and conditions: Add PCl5 or SOCl2 at r.t.p. / PCl3 with heating

Observations: P: No white fumes

Q: White misty fumes of HClevolved

Balanced equation(s) for positive test:

Or

Reagents and conditions: Aq Br2 or liquid Br2 at r.t.p.

Observations: P: Orange or Brown Br2 decolourised, white ppt formed for aq Br2.

Q: Orange or Brown Br2 remained.

Balanced equation(s) for positive test:

Or

Reagents and conditions: Acidified K2Cr2O7, heat

Observations: P: Orange K2Cr2O7 remained

Q: Orange K2Cr2O7 turned green

Balanced equation(s) for positive test:

Neutral FeCl3 is avoided as no equation can be written

Esterification is avoided as smell is not a good distinguishing test.

(b) /
R /
S

Reagents and conditions: Heat both compounds aq NaOH, then add heat with aqueous I2 + NaOH(aq).

Observations: R: Yellow ppt

S: No yellow ppt

Balanced equation(s) for positive test:

Reagents + conditions: ½ + ½

Observations: ½ m for positive observation, ½ m for negative observation

Equation: 1 m

3.Suggest how compound B can be formed from compound A. In each case, state

the reagents, conditions and intermediates (if any). [6 m]

(a) / /

Acidified KMnO4 should not be used as benzoic acid will be formed.

(b) / /

4.Draw the structural formulae of the compounds D, E and F.

[3 m]

[1 m each]

Accept the following structures of E and F as CH3I (without need for halogen carrier) may be

able to generate CH3+ forelectrophilic substitution on ring

(multiple substitution is acceptable also)

.