ThéveninNorton Equivalents
Lab-08 /
Lab Data Sheet – ENGR-43 Lab-08
Lab Logistics
Experimenter: Bruce Mayer, PERecorder:
Date: Mar06
Equipment Used (maker, model, and serial no. if available)
Fluke 8050A DMM; S/N 4630210
Tektronix PS280 DC Power Supply; S/N TW527171
Special Note
This laboratory exercise entails a significant amount of circuit construction & measurement effort/time. For this reason:
- Please COMPLETE ALL MEASUREMENTSin Table I, Table II, Table III, and Table VIIBEFOREcompleting any of the calculations
Directions
- Check out a DMM and Power/Probe Leads for the Power-Supply and DMM
- Go to the side counter, collect resistors, “bread board”, and leads required to construct the circuit shown inFigure 1. Configure the Power Supply Outputs to the INDEPENDENT mode as indicated in Figure 2.
- Make the Measurement and Calculations needed to complete Table I, Table II, Table III, Table IV, Table V, and Table VI.
Table I– Component Actual-Values by DMM Measurement
Vs1 = / 13.035 VVs2 = / 5.009 V
R1 = / 2.089 kΩ
R2 = / 3.803 kΩ
R3 = / 7.584 kΩ
R4 = / 11.472 kΩ
RL = / 3.478 kΩ
Table II–NodeVoltages: Calculations & DMM-Measurements
ValueDetermination / V1 / V2 / V3
Calculated / 8.368 V / 13.035 V / 3.456 V
Measured / 8.466 V / 13.057 V / 3.459 V
% / 1.17% / 0.0153% / 0.0868%
- Calculate Node Voltages using the component actual-values from Table I
- %J = 100x(VJ,meas – VJ,calc)/VJ,calc
Table III– Branch Currents: Calculations & DMM-Measurements
ValueDetermin. / I1 (mA) / I2 (mA) / I3 (mA) / I4 (mA) / Is1 (mA) / Is2 (mA) / IL (mA)
Calculated / -2.234 / 3.428 / -0.456 / 0.729 / -5.662 / 1.505 / 1.049
Measured / -2.182 / 3.419 / -0.453 / 0.733 / -5.573 / 1.442 / 0.992
% / 2.33% / 0.263% / 0.658% / 0.549% / 1.57% / 4.19% / 5.43%
- Calculate Branch Currents using the component actual-values from Table I
- %J = 100x(IJ,meas – IJ,calc)/IJ,calc
Table IV– Power Absorbed by Voltage Supplies: Component and VI Calculations
ValueCalculations / PVs1 / PVs2 / ΣPVsj
Component: Calc1 / -73.804 mW / 7.539 mW / 66.265 mW
Measured VI: Calc2 / -72.655 mW / 7.223 mW / 65.432 mW
% / 1.557% / 4.192% / 1.257%
- For ALL power calculations assume that the PASSIVE Sign convention relates component voltage-polarities and current-directions
- Calculation-1: Use the component actual-values from Table I
- Calculation-2: Use the measured values of V-across, and I-thru for the two supplies from Table II and Table III
- %J = 100x(PJ,meas – PJ,calc)/PJ,calc
Table V– Power Absorbed by Resistors: Component and VI Calculations
ValueCalcs / PR1 (mW) / PR2 (mW) / PR3 (mW) / PR4 (mW) / PRL (mW) / ΣPRj (mW)
Component:
Calc1 / 10.426 / 44.69 / 1.577 / 6.097 / 3.827 / 66.617
Measured
VI: Calc2 / 9.946 / 44.455 / 1.556 / 6.164 / 3.423 / 65.544
% / 4.603% / 0.526% / 1.33% / 1.099% / 10.56% / 1.611%
- For ALL power calculations assume that the PASSIVE Sign convention relates component voltage-polarities and current-directions
- Calculation-1: Use the component actual-values from Table I
- Calculation-2: Use the measured values of V-across, and I-thru for the two supplies from Table II and Table III
- %J = 100x(PJ,meas – PJ,calc)/PJ,calc
Table VI– Power Balance
ValueCalculations / ΣPVsj / ΣPRj / % Out of Balance, ΔOB%
Component: Calc1 / -66.265 mW / 66.617 mW / 0.265%
Measured VI: Calc2 / -65.432 mW / 65.544 mW / 0.0855%
- Calculation-1: Use the component-calculations from Table IV and Table V
- Calculation-2: Use the measured VI calculations from Table IV and Table V
- OB% by this Equation:
Directions (continued)
- Remove the Load Resistor, RL, from the circuit to leave OPEN that branch of the circuit as shown in Figure 3
- Make the measurements and calculations need to complete Table VII
Table VII– Thevenin Component Determination
Value / Quantity, and Determination-Method4.884 V / = Voc By DMM Measurment
3.383 mA / = Isc By DMM Measurment
- Hint: The DMM itself acts as the Short Circuit
1.444 kΩ / = RTH,VI = Voc/Isc
- Use DMM Measured Voc and Isc
1.4317 kΩ / = RTH,SD by Source Deactivation
- DeActivate the Voltage Sources by REMOVING them from the Ckt, and REPLACING them with a wire
- Measure using the DMM the resulting Resistance as seen from the Voc terminals
1.4379 kΩ / = RTH,avg = [RTH,VI + RTH,SD]/2
Directions (continued)
- In the Space Below Neatly Draw the THEVENIN Equivalent for the Circuit shown in Figure 3 with the Load Resistor REATTACHED. Use RTH,avg from Table VII.
- For the Thevenin Equivalent Circuit calculate the Load Current, IL, and mark its magnitude and direction on the circuit Diagram.
Directions (continued)
- In the Space Below Neatly Draw the NORTON Equivalent for the Circuit shown in Figure 3 with the Load Resistor REATTACHED. Use RTH,avg from Table VII.
- For the NORTON Equivalent Circuit calculate the Load Current, IL, and mark its magnitude and direction on the circuit Diagram.
Directions (continued)
- Return all lab hardware to the “as-found” condition
Directions (continued)
- QUESTION: How does IL by the Thevenin and Norton Equivalents compare to the DMM-Measured value from Table III?
Using the Single-Loop-Circuit method on the Thevenin form find IL as
Using the Current-Divider method on the Norton form find IL as
From Table III note the measured Load Current of 0.992 mA. Using the MEASURED Value as the BASELINE, find the Δ% for both equivalent Circuits
The Thevenin and Norton equivalents provide estimated Load Currents that are within less than ¼% of the measured value. For this experiment the Equivalent-Circuits Models yield excellent estimates for the physical quantities.
Run Notes/Comments
The Thevin/Norton Equivalents are very accurate for this circuit. This indicates that the BOTH the resistors and Volage-Source very closely approximate the LINEAR Circuit-Component ideal forms
©Bruce Mayer, PE • ChabotCollege •ENGR-43_Lab_08_Thevenin-Norton_TEST_110106.doc • Page 1