Question #1 / 25

Simplify.

squareroot 18/50

Be suretowriteyouranswer in lowestterms.

Answer:

Question #2 / 25

Rewritethefollowing in simplified radical form.

squareroot 20

Question #3 / 25

Rewritethefollowing in simplified radical form.

squareroot 12y^8

Assumethatall variables represent positive real numbers.

= 2y4

Question #4 / 25

Writethefollowingexpression in simplified radical form.

squareroot 75 t^9 w^10

Assumethatall variables represent positive real numbers.

= 5t4w5

Question #5 / 25

Simplify as much as possible.

3x^2 squareroot 96xw^2 + w squareroot 24x^5

Assumethatall variables represent positive real numbers.

3x2

=

Question #6 / 25

Simplify.

squareroot 3v^2 u^2 squareroot 15v^2u^7

Assumethatall variables represent positive real numbers.

=3v2u4

Answer:3v2u4

Question #7 / 25

Multiply.

(6 squareroot 10 +4 squareroot 5) (squareroot 10-8 squareroot 5)

Simplifyyouranswer as much as possible.

I didit in the post

Question #8 / 25

Rationalizethedenominator and simplify.

squareroot 77/ squareroot 55

Answer:

Question #9 / 25

Write in simplified radical formbyrationalizingthedenominator.

2 squareroot 3+4/ -2 squareroot 3+5

I didit in thefile “3 Questions”

Question #10 / 25

Solvefor ^v ,where ^v is a real number. (it looks likethe v is in the air orsquaredbutitisnot in theequation?)

squareroot v-11=7

(Ifthereis more thanonesolution, separatethemwithcommas.)

Solution

v-11=72=49

v=49+11=60

Answer: v=60

Question #11 / 25

Solvefor u, where u is a real number.

squareroot 7u-7 = squareroot 2u+2

(Ifthereis more thanonesolution, separatethemwithcommas.)

Solution:

7u-7=2u+2

7u-2u=2+7

5u=9

u=9/5

Answer: u=9/5

Question #12 / 25

Solvefor w, where w is a real number.

squareroot 5w+6=w

(Ifthereis more thanonesolution, separatethemwithcommas.)

Solution:

5w+6=w2

w2-5w-6=0

w= (5 ± 7)/2= 6,-1

Butonly w=6 checktheequation

Answer: w=6

Question #13 / 25

Forthefollowingrighttriangle, findtheside x length . Round youranswertothenearesttenth.

8 isonthe short side and x isonthe short side. Thelongside of thetriangleorbottomis 12

Can youclarifythetriangle ?

I didit in thefile “3 Questions”

Question #14 / 25

Simplify. There isa a big 8 and it looks likethe 2/3 is a squarerrot

8 2/3

Solution:

82/3==22=4

Answer: 4

Question #15 / 25

Compute thefollowing: 3 isontheoutside and looks small

.

3 squareroot -27

Solution:

Answer: -3

Question #16 / 25

Writethefollowing in simplified radical form. the 4 looks small and isontheoutside

4 squareroot 96

Answer: 2

Question #17 / 25

Writethefollowingexpression in simplified radical form. the 5 looks smallontheoutside

5 squareroot 160x^11 y^5

Assumethatall of the variables in theexpressionrepresent positive real numbers.

Solution

Answer: 2x2y

Question #18 / 25

Findtheroots of thequadraticequation:

w^2-3w+2=0

(Ifthereis more thanoneroot, separatethemwithcommas.)

Solution

w=(3±1)/2

Answer: 1,2

Question #19 / 25

Solve:

3u^2=u+4

(Ifthereis more thanonesolution, separatethemwithcommas.)

Solution

3u2-u-4=0

u=

Answer: 4/3,-1

Question #20 / 25

Solvetheequation

2y^2+4y+6=(y-1)^2

for y .

(Ifthereis more thanonesolution, separatethemwithcommas.)

Solution:

2y2+4y+6=y2-2y+1

y2+6y+5=0

y=

Answer: -1,-5

Question #21 / 25

Solve x^2=27, where x is a real number.
Simplifyyouranswer as much as possible.

Ifthereis more thanonesolution, separatethemwithcommas.

Solution:

x2=27 then: x=±

Answer: -33,33

Question #22 / 25

Solve (w-9)^2-72=0 , where w is a real number.
Simplifyyouranswer as much as possible.

Ifthereis more thanonesolution, separatethemwithcommas.

Solution:

(w-9)2=72

w-9=±72=±62

w=9±62

Answer: 9-,9+

Question #23 / 25

Compute thevalue of thediscriminant and givethenumber of real solutionstothequadraticequation.

7x^2-4x-1=0

Answer: discriminantis(-4)2-4(7)(-1)=16+28=44

2 real solutions

Question #24 / 25

Use thequadratic formula tosolvefor .

9x^2+x-2=0

(Ifthereis more thanonesolution, separatethemwithcommas.)

Solution:x=

Answer:

Question #25 / 25

When a ballisthrown, itsheight in feet h after t secondsisgivenbytheequation

h=vt-16t^2,

where v istheinitialupwardsvelocity in feet per second. If v=19 feet per second, findallvalues of t forwhich h=5 feet. Do not round anyintermediatesteps. Round youranswerto 2 decimal places.

(Ifthereis more thanoneanswer, enteradditionalanswerswiththebuttonthatsays "or".)

Solution:

Wehavetofind t where

5=19t-16t2

-16t2+19t-5=0

t =

t = 0.3937, 0.7938

Answer: 0.39, 0.79