Physics Worksheet
Newton’s 2nd Law – The Basics
For each of the situations shown, determine the required information:
(a)Fnet = 16.0 N [E]
a = 2.0 ms-2 [E] / (b)
Fnet = 10.0 N [W]
a = 5.0 ms-2 [W] / (c)
uniform motion
Fnet = ZERO
F1 = 10.0 N [E]
a = ZERO / (d)
uniform motion
Fnet = ZERO
F1 = 60.0 N [E]
a = ZERO / (e)
Fnet = 8.0 N [W]
a = 4.0 ms-2 [W]
(f)
Fnet = ZERO
a = ZERO
vi = 6.0 m/s [E]
vf = 6.0 ms-1 [E] / (g)
Fnet = ZERO
a = 0 m/s2
F2 = 20 N [W] / (h)
Fnet = 2.0 N [E]
a = 1.0 ms-2 [E] / (i)
Fnet = 16 N [E]
a = 1.6 ms-2 [E] / (j)
Fnet = 3.0 N [W]
a = 3.0 m/s2 [W]
F2 = 23 N [W]
(k)
Fnet = 20 N [E]
a = 2.0 m/s2 [E]
F1 = 25 N [E] / (l)
Fnet = 20 N [W]
a = 2.0 m/s2 [W]
F1 = - 15 N [E] / (m)
Fnet = 5.0 N [E]
a = 0.33 ms-2 [E]
F2 = 15 N [W] / (n)
Fnet = 0.50 N [W]
a = 0.50 m/s2 [W]
F2 = 20.5 N [W] / (o)
Fnet = 5.0 N [W]
a = 0.50 m/s2 [W]
F2 = 11.0 N [W]
(p)
Vi = 2.0 m/s [W]
Vf = 2.0 m/s [W]
Fnet = ZERO
a = ZERO
F2 = 50.0 N [W] / (q)
uniform motion
Fnet = ZERO
a = ZERO
F2 = 7.0 N [W] / (r)
Vi = zero
Vf = 1.0 ms-1 [E]
Fnet = 20 N [E]
a = 0.20 ms-2 [E]
Dt = 5.00 s / (s)
Vi = 4.0 m/s [E]
Vf = 2.7 ms-1 [E]
Fnet = 100 N [W]
a = 0.33 ms-2 [W]
Dt = 4.0 s / (t)
Vi = 10 m/s [W]
Vf = zero
Fnet = 60 N [E]
a = 1 ms-2 [E]
Dt = 10.0 s
(u)
Fnet = 0.01 N [E]
a = 0.10 m/s2 [E]
F2 = 3.99 N [W] / (v)
Fnet = 7.5 N [E]
a = 1.5 m/s2 [E]
F2 = - 4.5 N [W] / (w)
Dv = 17 m/s [E]
Fnet = 17 N [E]
F1 = 22 N [E]
a = 1.7 m/s2 [E]
Dt = 10.0 s / (x)
Fnet = 5.0 N [W]
a = 2.5 ms-2 [W]
F2 = 8.0 N [W] / (y)
Fnet = 100 N [W]
a = 0.33 m/s2 [W]
F2 = 200 N [W]