Set B
Aptitude Test
Find the odd man out.
1).1, 4, 9, 16, 20, 36, 49
A. / 1 / B. / 9C. / 20 /
/ D. / 49
Answer: Option C
Explanation:
The pattern is 12, 22, 32, 42, 52, 62, 72. But, instead of 52, it is 20 which to be turned out.
2).385, 462, 572, 396, 427, 671, 264
A. / 385 / B. / 427 /C. / 671 / D. / 264
Answer: Option B
Explanation:
In each number except 427, the middle digit is the sum of other two.
3).6, 9, 15, 21, 24, 28, 30
A. / 28 // B. / 21
C. / 24 / D. / 30
Answer: Option A
Explanation:
Each of the numbers except 28, is a multiple of 3.
Find out the wrong number in the series.
4). / 7, 8, 18, 57, 228, 1165, 6996A. / 8 / B. / 18
C. / 57 / D. / 228 /
E. / 1165
Ans:Option D
Explanation:
Let the given numbers be A, B, C, D, E, F, G.
Then, A, A x 1 + 1, B x 2 + 2, C x 3 + 3, D x 4 + 4, E x 5 + 5, F x 6 + 6 are the required numbers.
Clearly, 228 is wrong.
5). / Three numbers which are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. The sum of the three numbers is:A. / 75 /
/ B. / 81 /
C. / 85 /
/ D. / 89 /
Answer: Option C
Explanation:
Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 551 and 1073 = 29;
First number = / / 551 / / = 19;Third number = / / 1073 / / = 37.
29 / 29
Required sum = (19 + 29 + 37) = 85.
6). / Which of the following has the most number of divisors?
A. / 99 /
/ B. / 101 /
C. / 176 /
/ D. / 182 /
Answer: Option C
Explanation:
99 = 1 x 3 x 3 x 11
101 = 1 x 101
176 = 1 x 2 x 2 x 2 x 2 x 11
182 = 1 x 2 x 7 x 13
So, divisors of 99 are 1, 3, 9, 11, 33, .99
Divisors of 101 are 1 and 101
Divisors of 176 are 1, 2, 4, 8, 11, 16, 22, 44, 88 and 176
Divisors of 182 are 1, 2, 7, 13, 14, 26, 91 and 182.
Hence, 176 has the most number of divisors.
7). / There are two examinations rooms A and B. If 10 students are sent from A to B, then the number of students in each room is the same. If 20 candidates are sent from B to A, then the number of students in A is double the number of students in B. The number of students in room A is:
A. / 20 /
/ B. / 80 /
C. / 100 /
/ D. / 200 /
Answer: Option C
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x - 10 = y + 10 x - y = 20 .... (i)
and x + 20 = 2(y - 20) x - 2y = -60 .... (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
8). / If one-third of one-fourth of a number is 15, then three-tenth of that number is:
A. / 35 /
/ B. / 36 /
C. / 45 /
/ D. / 54 /
Answer: Option D
Explanation:
Let the number be x.
Then, / 1 / of / 1 / of x = 15 x = 15 x 12 = 180.
3 / 4
So, required number = / / 3 / x 180 / / = 54.
10
9). / X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last?
A. / 6 days /
/ B. / 10 days /
C. / 15 days /
/ D. / 20 days /
Answer: Option B
Explanation:
Work done by X in 4 days = / / 1 / x 4 / / = / 1 / .
20 / 5
Remaining work = / / 1 - / 1 / / = / 4 / .
5 / 5
(X + Y)'s 1 day's work = / / 1 / + / 1 / / = / 8 / = / 2 / .
20 / 12 / 60 / 15
Now, / 2 / work is done by X and Y in 1 day.
15
So, / 4 / work will be done by X and Y in / / 15 / x / 4 / / = 6 days.
5 / 2 / 5
Hence, total time taken = (6 + 4) days = 10 days.
14). / How many times in a day, the hands of a clock are straight?
A. / 22 /
/ B. / 24 /
C. / 44 /
/ D. / 48 /
Answer: Option C
Explanation:
In 12 hours, the hands coincide or are in opposite direction 22 times.
- In 24 hours, the hands coincide or are in opposite direction 44 times a day
Logical Section
In these series, you will be looking at both the letter pattern and the number pattern. Fill the blank in the middle of the series or end of the series.
1). / QAR, RAS, SAT, TAU, _____A. / UAV /
/ B. / UAT
C. / TAS / D. / TAT
Answer: Option A
Explanation:
In this series, the third letter is repeated as the first letter of the next segment. The middle letter, A, remains static. The third letters are in alphabetical order, beginning with R.
2). JAK, KBL, LCM, MDN, _____
A. / OEP / B. / NEO /C. / MEN / D. / PFQ
Answer: Option B
Explanation:
This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as a first letter in each subsequent three-letter segment.
3). P5QR, P4QS, P3QT, _____, P1QV
A. / PQW / B. / PQV2C. / P2QU /
/ D. / PQ3U
Answer: Option C
Explanation:
The first two letters, PQ, are static. The third letter is in alphabetical order, beginning with R. The number series is in descending order beginning with 5.
Three of the words will be in the same classification, the remaining one will not be. Your answer will be the one word that does NOT belong in the same classification as the others.
1). / Which word does NOT belong with the others?A. / book /
/ B. / index
C. / glossary / D. / chapter
Answer: Option A
Explanation:
An index, glossary, and chapter are all parts of a book. Choice a does not belong because the book is the whole, not a part.
2) Which word does NOT belong with the others?
A. / leopard / B. / cougarC. / elephant /
/ D. / lion
Answer: Option C
Explanation:
A leopard, cougar, and lion all belong to the cat family; an elephant does not.
Each problem consists of three statements. Based on the first two statements, the third statement may be true, false, or uncertain.
1). During the past year, Josh saw more movies than Stephen.
Stephen saw fewer movies than Darren.
Darren saw more movies than Josh.
If the first two statements are true, the third statement is
B. / false
C. / uncertain /
Answer: Option C
Explanation:
Because the first two sentences are true, both Josh and Darren saw more movies than Stephen. However, it is uncertain as to whether Darren saw more movies than Josh.
2). Rover weighs less than Fido.
Rover weighs more than Boomer.
Of the three dogs, Boomer weighs the least.
If the first two statements are true, the third statement is
B. / false
C. / uncertain
Answer: Option A
Explanation:
According to the first two statements, Fido weighs the most and Boomer weighs the least.
Pick out the most effective word(s) from the given words to fill in the blank to make the sentence meaningfully complete.
1.) / I was astounded at his ...... lack of knowledge about the Continent of Africa.A. / abundant / B. / colossal /
C. / huge / D. / great
Answer: Option B
2) The manner in which bombs exploded in five trains with in a short span of time suggests that it is a part of a ......
A. / game / B. / conspiracy /C. / villainy / D. / sabotage
Answer: Option B
3). The waiter hasn't brought the coffee ...... I've been here an hour already.
A. / till / B. / upC. / yet /
/ D. / still
Answer: Option C
4). When I was a child, I ...... to school everyday instead going by cycle.
A. / had walked / B. / walked /C. / have walked / D. / have been walking
Answer: Option B
Which of phrases given below each sentence should replace the phrase printed in bold type to make the grammatically correct? If the sentence is correct as it is, mark 'E' as the answer.
1).My doctor knew that I would eventually recover and do kind of work I would be doing before
A. / would have been doing / B. / would have doneC. / had been done / D. / had been doing /
E. / No correction required
Answer: Option D
2). Hardly does the sun rise when the stars disappeared.
A. / have the sun rose / B. / had the sun risen /C. / did the sun rose / D. / the sun rose
E. / No correction required
Answer: Option B
3) You will be late if you do not leave now
A. / did not leave / B. / leftC. / will not leave / D. / do not happen to leave
E. / No correction required /
Answer: Option E
4) We demonstrated to them how we were prepared the artistic patterns.
A. / are prepared / B. / have preparedC. / are preparing / D. / had prepared /
E. / No correction required
Answer: Option D
Antonyms
In the following questions choose the word which is the exact OPPOSITE of the given words.
1. / LOQUACIOUSA. / Reticent /
/ B. / Talkative
C. / Garrulous / D. / Verbose
Answer: Option A
2). REPEL
A. / Attend / B. / ConcentrateC. / Continue / D. / Attract /
Answer: Option D
3) NIGGARDLY
A. / Frugal / B. / ThriftyC. / Stingy / D. / Generous /
Answer: Option D
4). HAPHAZARD
A. / Fortuitous / B. / IndifferentC. / Deliberate /
/ D. / Accidental
Answer: Option C
Synonyms
1).MAYHEM
A. / Jubilation / B. / Havoc /C. / Excitement / D. / Defeat
Answer: Option B
2). SHIVER
A. / Feel / B. / RockC. / Tremble /
/ D. / Move
Answer: Option C
3). INSOMANIA
A. / Lethargy / B. / Sleeplessness /C. / Drunkenness / D. / Unconsciousness
Answer: Option B
4) REPERCUSSION
A. / Clever reply / B. / RecollectionC. / Remuneration / D. / Reaction /
Answer: Option D
Technical Section
What will be the output of the program?
#include<stdio.h>
int main()
{
char j=1;
while(j < 5)
{
printf("%d, ", j);
j = j+1;
}
printf("\n");
return 0;
}
A. / 1 2 3 ... 127B. / 1 2 3 ... 255
C. / 1 2 3 ... 127 128 0 1 2 3 ... infinite times
D. / 1, 2, 3, 4 /
Answer: Option D
2).
What will be the output of the program?
#include<stdio.h>
int main()
{
int x, y, z;
x=y=z=1;
z = ++x || ++y & ++z;
printf("x=%d, y=%d, z=%d\n", x, y, z);
return 0;
}
A. / x=2, y=1, z=1 // B. / x=2, y=2, z=1
C. / x=2, y=2, z=2 / D. / x=1, y=2, z=1
Answer: Option A
Explanation:
Step 1: x=y=z=1; here the variables x ,y, z are initialized to value '1'.
Step 2: z = ++x || ++y & ++z; becomes z = ( (++x) || (++y & ++z) ). Here ++x becomes 2. So there is no need to check the other side because ||(Logical OR) condition is satisfied.(z = (2 || ++y & ++z)). There is no need to process ++y & ++z. Hence it returns '1'. So the value of variable z is '1'
Step 3: printf("x=%d, y=%d, z=%d\n", x, y, z); It prints "x=2, y=1, z=1". here x is increemented in previous step. y and z are not increemented.
3). What will be the output of the program?