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ANNEXURE (Work sheets)
Table A. Common energy calculation for all treatment of potato cultivation
Sl. No. / Field operations / Energy sources / Amount / Calculation (in MJ) / Energy input (MJ/ha)1. / Land preparation / Land preparation by tractor with rotavator plus laddering / 2 times × 7.5 hrs. = 15 hrs. / [Wt. of Tractor (kg) / Life span (hrs.)] × MJ × hours of operation = [2500/12000] × 64.80 × 15 = 202.5 MJ
[Wt. of rotavator (kg) / Life span (hrs.)] × MJ × hours of operation = [400/6000] × 64.80 × 15 = 64.8 MJ / 202.5
64.8
Diesel consumption (3.5 litters/hr) / For 15 hrs. / = 3.5 × 15 = 52.5 litres
52.5 × 56.21 MJ = 2951.025 MJ / 2951.025
Driver (Human) / 1 MU (Men) / Men = 1 × 15 × 1.96 MJ = 29.4 MJ / 29.4
Laddering with bullock drawn wooden ladder / 2 hrs. / = 2 × 10.10 MJ = 20.20 MJ / 20.20
Human / 1 MU (Men) / Men = 1 × 2 × 1.96 MJ = 3.92 MJ / 3.92
Lay out, furrow making & channel preparation / 15 MU (Men) / Men = 15 × 8 × 1.96 MJ = 235.2 MJ / 235.2
2. / Sowing / Seed tuber / 2000 kg/ha / = 2000 × 3.6 MJ = 7200 MJ / 7200
Seed treatment chemical / 1 kg / = 1 × 120 MJ = 120 MJ / 120
Cutting of seed tuber & sowing cost / 45 MU (Men) / Men = 45 × 8 × 1.96 MJ = 705.6 MJ / 705.6
3. / Intercultural operation / Weeding / 20 MU / Men = 20 × 8 × 1.96 MJ = 316.6 MJ / 313.6
Earthing up / 30 MU / Men = 30 × 8 × 1.96 MJ = 470.4 MJ / 470.4
4. / Irrigation / Water lifting pump (Diesel motor 5 HP) / 7 times × 11.25 hrs. = 78.75 hrs. / [Wt. of the engine (kg) / Life span (hrs.)] × MJ × hours of operation = [150/10500] × 64.80 × 78.75 = 72.9 MJ / 72.9
Diesel consumption (0.5 litre/hr.) / For 78.75 hrs. / = 0.5 x 78.5 = 39.375 litres
39.375 × 56.31 MJ = 2217.21 MJ / 2217.21
Application / 20 MU / = 20 × 8 × 1.96 MJ = 313.6 MJ / 313.6
5. / Plant protection & surveillance / Chemical / 6 times / = 7.750 litres × 120 MJ × 6 (spray) = 5580 MJ / 5580
Application / 2 MU (Men) / Men= 2 × 8 × 1.96 MJ = 31.39 MJ / 31.36
6. / Dehaulming / 10 MU (Men) / Men = 10 × 8 × 1.96 MJ = 156.8 MJ / 156.8
7. / Harvesting of potato tubers, bagging, carrying / 45 MU / Men = 45 × 8 × 1.96 MJ = 705.6 MJ / 705.6
TOTAL / 22257.52
≈ 22258
MU, Man unit (1 MU = One man working for 8 hrs. per day)
Table B. Energy utilized through different nutritional sources in potato cultivation with each tested cultivar
Energy source / Energy utilized (MJ/ha) *N0 / N1 / N2 / N3 / N4
Nitrogen / 0 / 4545 / 9090 / 13635 / 18180
Phosphorus / 1665 / 1665 / 1665 / 1665 / 1665
Potassium / 1005 / 1005 / 1005 / 1005 / 1005
Total (N+P+K) / 2670 / 7215 / 11760 / 16305 / 20850
* Energy utilized = Amount of N/P/K nutrients (kg/ha) × equivalent energy (60.6, 11.1 and 6.7 MJ/kg for N, P2O5 and K2O respectively)