1 ANSC 221 NAME --------------------------
HOMEWORK 5 RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS ---ANSWERS---
FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN 12.1 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 5 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE 3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent) ANSWERS:
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN, CALCIUM, PHOSPHORUS,
---------- ---------- ----------
CORN 7.5 .02 .29
Oats 11 .10 .44
SOYBEAN MEAL 44.1 .25 .60
DICALCIUM PHOSPHATE 0 24.0 18.5
LIMESTONE 0 38 0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent TON
CORN 79.3 1586
Oats 5 100
SOYBEAN MEAL 12.7 253.9999
DICAL .9288108 18.57622
LIMESTONE .8538827 17.07765
SALT 0.25 5
TM Premix 0.10 2
Se PREMIX 0.05 1
VIT Premix 0.30 6
TYLAN-10 0.40 8
CU-SULFATE 0.10 2
OTHER 1.730645E-02 .3461289
------ ------
TOTAL 100 2000
PERCENT LYSINE IN RATION = .6045799
1 ANSC 221, Homework 5
ALGEBRAIC SOLUTION: PEARSON SQUARE SOLUTION:
(100)( .121 ) = ( .075 )(X) + ( .11 )( 5 ) + (100- 3 - 5 -X)( .441 )
PROTEIN CORN Oats SBM ( 5 ) ( .11 ) = .55
12.1 = .075 X + .55 + ( 92 -X)( .441 ) STEP 2: (100 lbs) ( .121 ) = 12.1
12.1 = .075 X + .55 + 40.572 - .441 X 12.1 - .55 = 11.55
12.1 - 40.572 - .55 = .075 X - .441 X
-29.022 = -.366 X STEP 3: 100- 5 - 3 = 92 (100-AMT Oats-AMT EMPTY)
79.3 = X 11.55 / 92 = 12.6
12.7 = 92 - X STEP 4:
7.5 ---------- 31.5 31.5 / 36.6 x 92 = 79.3
: :
: 12.6 :
: :
44.1 ---------- 5.1 5.1 / 36.6 x 92 = 12.7
---------
36.6
CORN = 79.3
Oats = 5
SBM = 12.7
MINERALS -- .6 PERCENT CA AND .5 PERCENT P
P IN GRAIN = (.0029)( 79.3 ) + (.0044)( 5 ) + (.006)( 12.7 ) = .22997 + .022 + 7.619999E-02 = .32817
CORN Oats SBM
P STILL NEEDED = .5 - .32817 = .17183
AMT DICAL TO USE = .17183 / .185 = .9288108
CA IN GRAIN + DICAL = (.0002)( 79.3 ) + (.0010)( 5 ) + (.0025)( 12.7 ) + (.24)( .9288108 ) = .2755246
.01586 + .005 + 3.174999E-02 + .2229146
CA STILL NEEDED = .6 - .2755246 = .3244754
LIMESTONE TO USE TO GET .3244754 LBS CA = .3244754 / .38 = .8538827
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
2 ANSC 221 NAME --------------------------
HOMEWORK 5 RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS ---ANSWERS---
FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN 17.6 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE 3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent) ANSWERS:
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN, CALCIUM, PHOSPHORUS,
---------- ---------- ----------
CORN 8.3 .02 .29
Oats 12.1 .10 .44
SOYBEAN MEAL 45.7 .25 .60
DICALCIUM PHOSPHATE 0 24.0 18.5
LIMESTONE 0 38 0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent TON
CORN 63.4 1268
Oats 9 180
SOYBEAN MEAL 24.6 492
DICAL .696973 13.93946
LIMESTONE .9198592 18.39718
SALT 0.25 5
TM Premix 0.10 2
Se PREMIX 0.05 1
VIT Premix 0.30 6
TYLAN-10 0.40 8
CU-SULFATE 0.10 2
OTHER .1831677 3.663354
------ ------
TOTAL 100 2000
PERCENT LYSINE IN RATION = .94794
2 ANSC 221, Homework 5
ALGEBRAIC SOLUTION: PEARSON SQUARE SOLUTION:
(100)( .176 ) = ( .083 )(X) + ( .121 )( 9 ) + (100- 3 - 9 -X)( .457 )
PROTEIN CORN Oats SBM ( 9 ) ( .121 ) = 1.089
17.6 = .083 X + 1.089 + ( 88 -X)( .457 ) STEP 2: (100 lbs) ( .176 ) = 17.6
17.6 = .083 X + 1.089 + 40.216 - .457 X 17.6 - 1.089 = 16.511
17.6 - 40.216 - 1.089 = .083 X - .457 X
-23.705 = -.374 X STEP 3: 100- 9 - 3 = 88 (100-AMT Oats-AMT EMPTY)
63.4 = X 16.511 / 88 = 18.8
24.6 = 88 - X STEP 4:
8.3 ---------- 26.9 26.9 / 37.4 x 88 = 63.4
: :
: 18.8 :
: :
45.7 ---------- 10.5 10.5 / 37.4 x 88 = 24.6
---------
37.4
CORN = 63.4
Oats = 9
SBM = 24.6
MINERALS -- .6 PERCENT CA AND .5 PERCENT P
P IN GRAIN = (.0029)( 63.4 ) + (.0044)( 9 ) + (.006)( 24.6 ) = .18386 + .0396 + .1476 = .37106
CORN Oats SBM
P STILL NEEDED = .5 - .37106 = .12894
AMT DICAL TO USE = .12894 / .185 = .696973
CA IN GRAIN + DICAL = (.0002)( 63.4 ) + (.0010)( 9 ) + (.0025)( 24.6 ) + (.24)( .696973 ) = .2504535
.01268 + 9.000001E-03 + 6.149999E-02 + .1672735
CA STILL NEEDED = .6 - .2504535 = .3495465
LIMESTONE TO USE TO GET .3495465 LBS CA = .3495465 / .38 = .9198592
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
3 ANSC 221 NAME --------------------------
HOMEWORK 5 RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS ---ANSWERS---
FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN 18.1 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 15 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE 3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent) ANSWERS:
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN, CALCIUM, PHOSPHORUS,
---------- ---------- ----------
CORN 7.5 .02 .29
Oats 12.5 .10 .44
SOYBEAN MEAL 48.8 .25 .60
DICALCIUM PHOSPHATE 0 24.0 18.5
LIMESTONE 0 38 0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent TON
CORN 57.6 1152
Oats 15 300
SOYBEAN MEAL 24.4 488
DICAL .6516756 13.03351
LIMESTONE .937047 18.74094
SALT 0.25 5
TM Premix 0.10 2
Se PREMIX 0.05 1
VIT Premix 0.30 6
TYLAN-10 0.40 8
CU-SULFATE 0.10 2
OTHER .2112772 4.225545
------ ------
TOTAL 100 2000
PERCENT LYSINE IN RATION = .9864601
3 ANSC 221, Homework 5
ALGEBRAIC SOLUTION: PEARSON SQUARE SOLUTION:
(100)( .181 ) = ( .075 )(X) + ( .125 )( 15 ) + (100- 3 - 15 -X)( .488 )
PROTEIN CORN Oats SBM ( 15 ) ( .125 ) = 1.875
18.1 = .075 X + 1.875 + ( 82 -X)( .488 ) STEP 2: (100 lbs) ( .181 ) = 18.1
18.1 = .075 X + 1.875 + 40.016 - .488 X 18.1 - 1.875 = 16.225
18.1 - 40.016 - 1.875 = .075 X - .488 X
-23.791 = -.413 X STEP 3: 100- 15 - 3 = 82 (100-AMT Oats-AMT EMPTY)
57.6 = X 16.225 / 82 = 19.8
24.4 = 82 - X STEP 4:
7.5 ---------- 29 29 / 41.3 x 82 = 57.6
: :
: 19.8 :
: :
48.8 ---------- 12.3 12.3 / 41.3 x 82 = 24.4
---------
41.3
CORN = 57.6
Oats = 15
SBM = 24.4
MINERALS -- .6 PERCENT CA AND .5 PERCENT P
P IN GRAIN = (.0029)( 57.6 ) + (.0044)( 15 ) + (.006)( 24.4 ) = .16704 + .066 + .1464 = .37944
CORN Oats SBM
P STILL NEEDED = .5 - .37944 = .12056
AMT DICAL TO USE = .12056 / .185 = .6516756
CA IN GRAIN + DICAL = (.0002)( 57.6 ) + (.0010)( 15 ) + (.0025)( 24.4 ) + (.24)( .6516756 ) = .2439222
.01152 + .015 + .061 + .1564022
CA STILL NEEDED = .6 - .2439222 = .3560778
LIMESTONE TO USE TO GET .3560778 LBS CA = .3560778 / .38 = .937047
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
4 ANSC 221 NAME --------------------------
HOMEWORK 5 RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS ---ANSWERS---
FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN 12.3 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 10 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE 3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent) ANSWERS:
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN, CALCIUM, PHOSPHORUS,
---------- ---------- ----------
CORN 8.1 .02 .29
Oats 12.7 .10 .44
SOYBEAN MEAL 48.7 .25 .60
DICALCIUM PHOSPHATE 0 24.0 18.5
LIMESTONE 0 38 0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent TON
CORN 77.2 1544
Oats 10 200
SOYBEAN MEAL 9.800003 196.0001
DICAL .9368649 18.7373
LIMESTONE .8558223 17.11645
SALT 0.25 5
TM Premix 0.10 2
Se PREMIX 0.05 1
VIT Premix 0.30 6
TYLAN-10 0.40 8
CU-SULFATE 0.10 2
OTHER 7.312775E-03 .1462555
------ ------
TOTAL 100 2000
PERCENT LYSINE IN RATION = .5645201
4 ANSC 221, Homework 5
ALGEBRAIC SOLUTION: PEARSON SQUARE SOLUTION:
(100)( .123 ) = ( .081 )(X) + ( .127 )( 10 ) + (100- 3 - 10 -X)( .487 )
PROTEIN CORN Oats SBM ( 10 ) ( .127 ) = 1.27
12.3 = .081 X + 1.27 + ( 87 -X)( .487 ) STEP 2: (100 lbs) ( .123 ) = 12.3
12.3 = .081 X + 1.27 + 42.369 - .487 X 12.3 - 1.27 = 11.03
12.3 - 42.369 - 1.27 = .081 X - .487 X
-31.339 = -.406 X STEP 3: 100- 10 - 3 = 87 (100-AMT Oats-AMT EMPTY)
77.2 = X 11.03 / 87 = 12.7
9.800003 = 87 - X STEP 4:
8.1 ---------- 36 36 / 40.6 x 87 = 77.2
: :
: 12.7 :
: :
48.7 ---------- 4.599999 4.599999 / 40.6 x 87 = 9.800003
---------
40.6
CORN = 77.2
Oats = 10
SBM = 9.800003
MINERALS -- .6 PERCENT CA AND .5 PERCENT P
P IN GRAIN = (.0029)( 77.2 ) + (.0044)( 10 ) + (.006)( 9.800003 ) = .22388 + .044 + 5.880002E-02 = .32668
CORN Oats SBM
P STILL NEEDED = .5 - .32668 = .17332
AMT DICAL TO USE = .17332 / .185 = .9368649
CA IN GRAIN + DICAL = (.0002)( 77.2 ) + (.0010)( 10 ) + (.0025)( 9.800003 ) + (.24)( .9368649 ) = .2747876
.01544 + .01 + 2.450001E-02 + .2248476
CA STILL NEEDED = .6 - .2747876 = .3252124
LIMESTONE TO USE TO GET .3252124 LBS CA = .3252124 / .38 = .8558223
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so