STAT 211
Practice Exam
Exam 1
Use the following Data Set for Questions 1 through 4: 11, 21, 33, 12, 8, 14, 27, 11, 13, 1
- Find the sample mean of the data set
- 12.5
- 15.1
- 14.8
- 16.3
- 11.0
- Find the sample median of the data set
- 12.5
- 15.1
- 14.8
- 16.3
- 11.0
- Find the sample mode of the data set
- 12.5
- 15.1
- 14.8
- 16.3
- 11.0
- Find the sample Inter Quartile Range of the data set
- 8.00
- 10.75
- 6.50
- 10.00
- 9.50
- How are variance and standard deviation related?
- Variance is ALWAYS the square of the standard deviation
- Standard Deviation is SOMETIMES the square of the variance
- Variance is SOMETIMES the square of the variance
- Standard deviation is ALWAYS the square of the variance
- There is no exact relation, although they're usually close to one another
- Randomly roll one 12-sided die. The probability of getting a 4 or 5 is
- 1/6
- 2/6
- 3/6
- 4/6
- None of the above
- The probability that my microphone works is .20. What is the probability that my microphone does not work.
- 0
- .5
- .80
- -.80
- None of the above
Exam 2
- On a multiple choice exam, there are 4 possible answers to each of 60 questions. What is the expected number of correct answers if a student guesses on each question?
- 15
- 4
- 1
- .25
- 35% of apples purchased at a grocery store contain unhealthy levels of pesticides. A random sample of 6 apples is obtained. What is the probability that exactly 2 apples have an unhealthy level of pesticides?
- .647
- .353
- .672
- .328
- Which of the following corresponds to the probability of getting more than 8 successes in a binomial experiment?
- Assuming you guess on every question, what is the probability of passing your STAT 211 Exam if there are 20 questions and each question has 5 possible answers? (12 Correct is Passing)
- .9999
- .0001
- .6000
- .2000
- Suppose that deer cross a stretch of highway at a rate of 4 per hour. What is the probability that exactly 6 deer will cross the stretch of highway in one hour?
- .1107
- .8893
- .8958
- .1042
- Suppose that deer cross a stretch of highway at a rate of 4 per hour. What is the probability that between 5 and 8 deer (inclusive) will cross the stretch of highway in one hour?
- .3498
- .1935
- .6502
- .8065
- What is the standard deviation of the number of deer who cross the highway stretch in 4 hours?
- 2
- 4
- 8
- 16
- The time that it takes to travel from Morgantown to Pittsburgh is normally distributed with a mean of 1 hour and 30 minutes and a standard deviation of 5 minutes. What is the probability that a randomly selected car makes it to Pittsburgh in less than 1 hour and 45 minutes?
- .0014
- .1587
- .9987
- .8413
- The time that it takes to travel from Morgantown to Pittsburgh is normally distributed with a mean of 1 hour and 30 minutes and a standard deviation of 5 minutes. What is the probability that a randomly selected car makes it to Pittsburgh in more than 1 hour and 25 minutes?
- .0014
- .1587
- .9987
- .8413
- The average lifespan of a cat is 15 years with a standard deviation of 1 year. Kathryn has a house filled with 25 cats. What is the mean and standard deviation of the sampling distribution of the sample mean of cat life spans?
- The average lifespan of a cat is 16 years with a standard deviation of 1 year. Kathryn has a house filled with 25 cats. What is the probability that the mean cat lifespan will exceed 16.2 years?
- .5792
- .4207
- .8413
- .1587
- Which of the following would result in a decrease in the width of a confidence interval for a population mean?
- An decrease in the sample size
- An increase in the sample size
- A decrease in the sample mean
- An increase in the confidence level
- An increase in the standard error
- What effect does increasing my sample mean () have on the width of my confidence interval?
- Increases the width
- Decreases the width
- Has no effect on the width
- Increases or Decreases the width depending on if the sample mean is positive or negative
- The exam 2 completion time for 25 STAT 211 students has a sample mean of 40 minutes with a standard deviation of 5 minutes. Compute the 95% confidence interval on the mean completion time of all STAT 211 students.
- (39.608, 40.392)
- (39.922, 40.078)
- (38.040, 41.960)
- (38.355, 41.645)
- Using the Normal Distribution Table, find the area under the normal distribution curve between Z=-1.63 and Z=2.03
- .0727
- .9272
- .9788
- .0516
Exam 3
For each of the following scenarios, find the null and alternative hypotheses; compute the appropriate test statistic; make the appropriate decision and conclusion; note any conditions to use the test:
- I claim that the average monthly rent cost for a 1 bedroom apartment in Morgantown is more than $575. A sample of 12 apartments has an average monthly rent cost of $650 and a standard deviation of $100. At alpha = .05, test my claim.
- T=
- Using the T-Table with 11 degrees of freedom, our p-value is between .01 and .02
- Both of these values are less than .05, reject
- We have enough evidence at the .05 level to conclude that the average monthly rent cost for a 1 bedroom apartment in Morgantown is greater than $575.
- Because our sample size was <20, a t-test is appropriate
- About 80% of students pass their statistics class on their first attempt. Suppose the department chair at WVU speculates that this value is less than 80% at WVU. He takes a sample of 250 students at WVU and found 156 of them passed on their first attempt. Use alpha = .10
- Z=
- Using the Z table, our p-value is .2389
- Our p value is > .10, fail to reject
- We do not have enough evidence at the .10 level to conclude that the proportion of students who pass their statistics class on their first attempt at WVU is less than 80%.
- We require that
- Students were asked, “Would you recommend your English teacher to a student who needs the class in the future?” Of the 120 students who have had Dr. A in the past, 75% said yes, and of the 78 students who have had Dr. B in the past, 65% said yes. Do we have enough evidence to conclude that, for the populations represented by these students, a different proportion of students of Dr. A’s would answer yes to this question? Use alpha = .10
- Z=
- Using the Z table, our p-value is .0681, we must multiply it by 2, so p-value = .1362
- Our p value is > .10, fail to reject
- We do not have enough evidence at the .10 level to conclude that a different proportion of students of Dr. A’s would answer yes to the question.
- We require that
- A student is interested in whether the grade distribution of STAT 211 students follows10% A’s, 25% B’s, 30% C’s 25% D’s 10% F’s. The student obtains a sample of 66 grades. The observed counts were 14 A’s, 23 B’s, 15 C’s, 9 D’s, 5 F’s. Test the hypothesis at the .05 level (See Extra Credit Assignment 2)
- Using the table with 4 degrees of freedom, our p-value is between .005 and .0025
- Both of our p values are <.05,reject
- We have enough evidence at the .05 level to conclude that the distribution of 10% A’s, 25% B’s, 30% C’s 25% D’s 10% F’s is not the correct distribution
- We require that