Test/GT-9/Set-P Mittal Sir
III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.
email : , website : www.bmcchemistry.com
GT-9
TEST-/11th, 12th & 12th Passed
Topic : Class XI 2nd Book
Date : 18 Feb 2015
Max Marks : 120 Time : 45 minutes
Section - I
Rapid Fire (+2/0)
This section contains 10 questions. In these questions for every ASSERTION a REASON is given, If Reason correctly explain Assertion then mark option ‘a’ in all other cases mark option ‘b’.
1. ASSERTION : CCl4 can not be hydrolysed
REASON : Carbon can not increase its coordination number greater than 4.
2. ASSERTION : E°Li+/Li is most negative among alkali metals
REASON : Li+(g) + H2O ® Li+(aq) DH of this reaction is highly negative
3. ASSERTION : BeCO3 is kept in atmosphere of CO2
REASON : In BeCO3 very weak lattices are found hence equilibrium of reaction
BeCO3 BeO + CO2 remain towards right even at room temp.
(s) (s) (g)
4. ASSERTION : Small amount of Glycerol is added in H2O2 bottles
REASON : Glycerol decrease the rate of decomposition of H2O2
5. ASSERTION : Boric acid is a two dimensional solid
REASON : Hydrogen bonding stabilize molecules of Trigonal H3BO3
6. ASSERTION : For nitration of benzene reactivity C6H6 = C6D6
REASON : Elimination of H+ is not a rate determining step
7. ASSERTION : B–F bond in BF3 is slightly shorter than expected
REASON : BF3 is a weaker Lewis acid
8. ASSERTION : Nitrogen in trisilyl amine is planar
REASON : lone pair of nitrogen does not participate in bonding
9. ASSERTION : In B2H6 all ‘H’ are not same
REASON : Two ‘H’ form electron deficient bonds
10. ASSERTION : Enthalpy of combustion of CH2 = CH2 >
REASON : Lesser the stability of alkene, higher the enthalpy of combustion.
Section - II
Single Correct Answer Type (+4/-1)
This section contains 25 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONLY ONE is correct.
11. H2O2 + O3 ® H2O + 2 O2
500 ml of ‘xv’ H2O2 was required to react with 1 mol of ozone. The value of ‘x’ is –
(a) 11.2 (b) 5.6 (c) 22.4 (d) 44.8
12. In the product of reaction Na2S2O3 + I2 ®
The oxidation state of sulphur is (are)
(a) +6 (b) +6 & 0 (c) +5 & 0 (d) +5 & +6
13. O
C – O the product is - - - - , and due to - - - -
‘A’ ‘B’
O
(a) C – O , ring ‘A’ is deactivated by – COOPh group.
Cl
O
(b) C – O Cl , ring ‘B’ is activated by – OCOPh group.
O
(c) Cl C – O , ring ‘A’ is activated by – COOPh group.
O Cl
(d) Cl C – O , ring ‘B’ is deactivated by – OCOPh group.
14. The most stable among the following is –
OCH3 CH3 NO2
(a) (b) (c) (d)
H
H Cl H Cl H Cl Cl
15. In which case the product is aromatic
Cl
(a) (b) (c) Cl (d) none of these
16. Among the following the total number of compounds which have ‘pKa’ greater than pKa of H2O at 25°C
COOH
HC º CH, CH3COOH, , CH2 = CH2, D2O, CH3 – CH3, H2O2
(a) 3 (b) 4 (c) 5 (d) 2
17. Total number of geometrical isomers of the compound are CH3 – CH = CH – CH = CH – CH3
(a) 2 (b) 3 (c) 4 (d) 5
18. 0.25 gm of an organic compound was kjeldhelized. The NH3 evolved was absorbed in 250 ml of H2SO4 solution. The residual acid required 450 ml of NaOH solution. The % of nitrogen in organic compound is
(a) 14% (b) 28% (c) 42% (d) 56%
19. Total number of sigma bonds in this compound are
(a) 16 (b) 17 (c) 18 (d) 19
20. CH3 – C º CH P Q
The product formed is –
(a) 1-Butene (b) cis-2-butene (c) trans-2-butene (d) Propene
21. In B2H6 two type of B – H bonds are found B – Ht and B – Hb (t Þ terminal, bÞ bridge) the bond length has relation
(a) B – Ht = B – Hb (b) B – Ht > B – Hb (c) B – Ht < B – Hb
(d) Two type of B – Hb bonds one is longer while other is shorter
22. List – I List - II
(P) MgH2 (i) Moderator in nuclear power plant
(Q) (BN)x (ii) graphite like structure
(R) B3N3H6 (iii) Planar compound
(S) D2O (iv) Polymeric
(a) P – i, Q – ii, R – iii, S – iv (b) P – iv, Q – ii, R – iii, S – i
(c) P – iv, Q – iii, R – ii, S – i (d) P – i, Q – iii, R – ii, S – iv
23. Total number of mono substitution products (only structural isomers) of
CH3 – (CH2)2 – CH(CH3)2 are
(a) 3 (b) 4 (c) 5 (d) 6
24. OMe I.U.P.A.C name of the compound is –
Cl (a) 3-Bromo-6-Chloro anisol
(b) 5-Bromo-2-Chloro anisol
Br (c) 1-Bromo-4-Chloro-3-methoxy benzene
(d) 4-Bromo-1-Chloro-2-methoxy benzene
25. When sodium metal is dissolved in liquid NH3
(a) The solution show conductivity due to presence of H+
(b) The solution show reducing nature due to presence of H+
(c) the solution is paramagnetic due to presence of solvated electrons e– (NH3)x
(d) all of these
26. ZSM – 5 contain
(a) Pyro silicate (b) ortho silicate (c) cyclic silicate (d) three dimensional silicates
27. 1 mol of a substance (X) was treated with an excess of water. 2 moles of readily combustible gas were produced along with solution which when reacted with CO2 gas produced a white turbidity. The substance (X) could be
(a) Ca (b) CaH2 (c) Ca(OH)2 (d) Ca(NO3)2
28. In paper chromatography the stationary and mobile phases are respectively
(a) solid, solid (b) solid, liquid (c) liquid, liquid (d) liquid, solid
29. CH3 – CH – CH2 – CH2 , CH3 – CH2 – CH2 – CH2
OPh [II]
[I]
CH3 – CH – CH2 – CH2 , CH3 – CH2 – CH2 – CH2
OPh
[III] [IV]
The correct statement is
(a) I > II & III < IV due to +I effect of –OPh
(b) I < II & III > IV due to –I effect of –OPh
(c) I > II & III < IV due to –I effect of –OPh
(d) I < II & III > IV due to +I effect of –Oph
(Ph Þ Phenyl)
30. Total number of hyperconjugates possible in the intermediate formed during addition of HBr on 1-Pentene. (Consider only one product)
(a) 5 (b) 6 (c) 7 (d) 8
31. Column – I Column – II (Colour in Lassaigne mix. test)
(P) CH3NH2 (i) White colour with AgNO3
(Q) CH3Cl (ii) Violet colour with sodium nitroprusside
(R) CH3SH (iii) Blue colour with FeSO4 & conc H2SO4
(S) (CH3)3P (iv) Yellow colour with ammonium molybdate
(a) P – iii, Q – i, R – ii, S – iv (b) P – i, Q – iii, R – iv, S – ii
(c) P – ii, Q – i, R – iii, S – iv (d) P – iv, Q – i, R – iii, S – ii
32. O O OH O
I II III IV
(A) I & II are conjugating structures
(B) I & III are Tautomers
(C) I & IV are Geometrical isomers
The correct choices are
(a) A & C (b) B & C (c) C only (d) All A, B & C
33. Column-I Column-II
(P) CH3 – CH = CH2 (i) Wurtz reaction
(Q) CH3 – CH = CH2 (ii) Friedal craft reaction
(R) + CH3COCl (iii) Free radical as intermediate
(S) C2H5Br (iv) All steps in propagation are exothermic
(a) P – iv, Q – iii, R – ii, S – i (b) P – iii, Q – iv, R – ii, S – i
(c) P – iv, Q – iii, R – i, S – ii (d) P – iii, Q – iv, R – i, S – ii
34. In Kolbe’s electrolysis of CH3COOK(aq). The gas which is not formed is
(a) CH3 – CH3 (b) H2 (c) CO2 (d) CH3CH2CH3
35. The pair of substances that gives the same products on reaction with water is
(a) Mg and MgO (b) Sr and SrO (c) Ca and CaH2 (d) Be and BeO
III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.
email : , website : www.bmcchemistry.com
GT-9
TEST – 11th, 12th & 12th Passed
Topic : Class XI 2nd Book
Date : 18 Feb 2015
Max Marks : 120 Time : 45 minutes
Note : Write your name and roll no. above in box before filling the answers.
Section – I Section – II
(Rapid Fire (+2/0) (Straight Objective Type +4/-1)
A B A B C D A B C D
1. 11. 26.
2. 12. 27.
3. 13. 28.
4. 14. 29.
5. 15. 30.
6. 16. 31.
7. 17. 32.
8. 18. 33.
9. 19. 34.
10. 20. 35.
21.
22.
23.
24.
25.
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