Punnett Square Practice Problems Answers

1. WW x Ww 0%

W / W
W / WW / WW
w / Ww / Ww

2. WW x ww 0%

W / W
w / Ww / Ww
w / Ww / Ww

3. Hh x hh

H / h
h / Hh / hh
h / Hh / hh

4. Hh – Horns

hh – No horns

5. FF x ff so that all children will be green.

F / F
f / Ff / Ff
f / Ff / Ff

6. Ff x Ff

FF – Green, Ff – Green, ff – Yellow-striped

F / f
F / FF / Ff
f / Ff / ff

7. RR x rr 100% round

R / R
r / Rr / Rr
r / Rr / Rr

8. Yy x Yy 75% yellow and 25% green

Y / y
Y / YY / Yy
y / Yy / yy

9. ss x Ss 50% curled, 50% straight

s / s
S / Ss / Ss
s / ss / ss

10. Ee x Ee 75% erect ears, 25% droopy ears

E / e
E / EE / Ee
e / Ee / ee

11. Dad – Rr, Mom – Rr, Son - rr

12. CC x Cc 50% Curly, 50% Wavy

C / C
C / CC / CC
c / Cc / Cc

13. WW x WP 50% White, 50% Striped

W / W
W / WW / WW
P / WP / WP

* I should have changed this to W and w – in this case, the P = w.

14. rr x Rr 50% roan, 50% white

1 roan: 1 white

Y / y
Y / YY / Yy
y / Yy / yy

15. Farmer only wants red fur (RR) so he should only cross RR x RR if he wants it guaranteed. Any other crosses would result in different colors.

16. Codominance because both colors are present.

17. I’ll use the letter B

BB = Black, bb = tan, Bb = tabby

Bb x BB 0% Tan

B / b
B / BB / Bb
B / BB / Bb

17-2. BB x bb

B / B
b / Bb / Bb
b / Bb / Bb

18. Bb

19. Bb x Bb 1 Blue: 2 Silver : 1 White

B / b
B / BB / Bb
b / Bb / bb


20. Rr and Rr

R / r
R / RR / Rr
r / Rr / rr

30. No, they cannot produce a child that is ii.

IBi x IAIB

IB / i
IA / IAIB / IAi
IB / IBIB / IBi

IBIB x IAIB

IB / IB
IA / IAIB / IAIB
IB / IBIB / IBIB

31. IAi x IBi

IB / i
IA / IAIB / IAi
i / IB i / ii

32. IAIB – 25%, IAi – 25%, IB I – 25%

33. ii x IAIB

IA / IB
i / IAi / IBi
i / IAi / IBi