Punnett Square Practice Problems Answers
1. WW x Ww 0%
W / WW / WW / WW
w / Ww / Ww
2. WW x ww 0%
W / Ww / Ww / Ww
w / Ww / Ww
3. Hh x hh
H / hh / Hh / hh
h / Hh / hh
4. Hh – Horns
hh – No horns
5. FF x ff so that all children will be green.
F / Ff / Ff / Ff
f / Ff / Ff
6. Ff x Ff
FF – Green, Ff – Green, ff – Yellow-striped
F / fF / FF / Ff
f / Ff / ff
7. RR x rr 100% round
R / Rr / Rr / Rr
r / Rr / Rr
8. Yy x Yy 75% yellow and 25% green
Y / yY / YY / Yy
y / Yy / yy
9. ss x Ss 50% curled, 50% straight
s / sS / Ss / Ss
s / ss / ss
10. Ee x Ee 75% erect ears, 25% droopy ears
E / eE / EE / Ee
e / Ee / ee
11. Dad – Rr, Mom – Rr, Son - rr
12. CC x Cc 50% Curly, 50% Wavy
C / CC / CC / CC
c / Cc / Cc
13. WW x WP 50% White, 50% Striped
W / WW / WW / WW
P / WP / WP
* I should have changed this to W and w – in this case, the P = w.
14. rr x Rr 50% roan, 50% white
1 roan: 1 white
Y / yY / YY / Yy
y / Yy / yy
15. Farmer only wants red fur (RR) so he should only cross RR x RR if he wants it guaranteed. Any other crosses would result in different colors.
16. Codominance because both colors are present.
17. I’ll use the letter B
BB = Black, bb = tan, Bb = tabby
Bb x BB 0% Tan
B / bB / BB / Bb
B / BB / Bb
17-2. BB x bb
B / Bb / Bb / Bb
b / Bb / Bb
18. Bb
19. Bb x Bb 1 Blue: 2 Silver : 1 White
B / bB / BB / Bb
b / Bb / bb
20. Rr and Rr
R / RR / Rr
r / Rr / rr
30. No, they cannot produce a child that is ii.
IBi x IAIB
IB / iIA / IAIB / IAi
IB / IBIB / IBi
IBIB x IAIB
IB / IBIA / IAIB / IAIB
IB / IBIB / IBIB
31. IAi x IBi
IB / iIA / IAIB / IAi
i / IB i / ii
32. IAIB – 25%, IAi – 25%, IB I – 25%
33. ii x IAIB
IA / IBi / IAi / IBi
i / IAi / IBi