Name______
Physics 181 – Electricity and Magnetism: Exam 1
Important physical constants (may or may not be needed)
G = 6.6710-11 Nm2/kg2g= 9.8 m/s2ke = 1/4o = 8.99109 Nm2/C2o = 8.8510-12 C2/ Nm2
e = 1.6010-19 Cme = 9.1110-31 kgmp = 1.6710-27 kg
G=giga=109, M=mega=106, k=kilo=103; c=centi=10-2, m=milli=10-3, =micro=10-6, n=nano=10-9, p=pico=10-12
- (12 Points) A positively charged insulating rod is brought close to an object that is suspended by a string. If the object is attracted toward the rod we can conclude:
- the object initially had an excess of positive charge
- the object initially had an excess of negative charge
- the object was initially uncharged
- either (b) or (c) may be true
- that none of the above are true
- (12 Points) As used in the definition of electric field intensity, a “test charge”:
- has zero charge
- has charge of magnitude 1 C
- has charge of magnitude 1.6010-19 C
- must have a negative charge
- none of the above
- (12 Points) Electric field lines:
- are vectors in the direction of the electric field
- form closed loops
- are trajectories of a test charge
- cross each other in the region between two point charges
- are none of the above
- (12 Points) Choose the correct statement:
- The potential of a negatively charged conductor must be negative
- A proton tends to go from a region of high potential to a region of low potential
- If E=0 at a point P then V must be zero at P
- If V=0 at a point P then E must be zero at P
- None of the above are correct
- (12 Points) Experimenter A uses a test charge q0 and experimenter B uses a test charge 2q0 to measure an electric field produced by stationary charges. A finds a field that is:
- the same as the field found by B
- greater than the field found by B
- less than the field found by B
- either greater or less than the field found by B, depending on the masses of the test charges
- either greater or less than the field found by B, depending on the accelerations of the test charges
- (12 Points) A hollow metal sphere is charged to a potential V. The potential at its center is:
- V
- 0
- –V
- 2V
- need more information
Show work on problems 7-12. A correct answer with no work is worth 0 points.
- (15 points)A 5.0 C point charge is placed at the center of a cube. The electric flux in Nm2/C through the cube is:
- 0
- 7.1104
- 9.4104
- 1.4105
- 5.6105
- (18 points) A 200 N/C electric field is in the positive x direction. The acceleration on an electron (mass=me, charge=-e) in this field is:
- 3.51013 m/s2, in the positive x direction
- 3.51013 m/s2, in the negative x direction
- 3.210-17 m/s2, in the positive x direction
- 3.210-17 m/s2, in the negative x direction
- 0
- (20 points) A 55 nC charge is fixed at the origin. A –23 nC charge is moved from x=3.5 cm on the x axis to y=4.3 cm on the y axis. The change in potential energy is:
- 3.1 mJ
- –3.1 mJ
- 60 J
- -60 J
- 0
- (25 points) A proton (mass=mp, charge=+e) moves from point A to point B under the influence of electrostatic force only. At point A the proton moves with a speed of 50 km/s. At point B the speed of the proton is 80 km/s. Determine the potential difference V=Vb-Va
- +20 V
- –20 V
- -27 V
- +27 V
- –40 V
- (30 points) If Q=80 nC, a=3.0 m, and b=4.0 m in the figure below, what is the magnitude of the electric field at point P?
- 45 N/C
- 70 N/C
- 24 N/C
- 47 N/C
- 92 N/C
- (30 points) A uniform linear charge density of 7.0 mC/m is distributed along the y-axis from y=2 m to y=5 m. Which of the following integrals is correct for the magnitude of the force in N on a 1 C charge placed at the origin (with y in meters)?