Notes: Chemical Composition & Formulas

Percent Composition

Mass percent = weight percent

  • The proportion of a given atom in a compound, expressed as a %
  • Based on atomic masses
  • The mass fraction is converted to a mass percent by multiplying by 100%

Example:

The formula for ethanol is C2H5OH. Calculate the mass percent of each element in this compound.

  • Step 1: Determine the molar mass
  • Step 2: Determine the mass fraction & mass percent for each
  • Step 3: Check your work by making sure the % of each atom add up to approximately 100% (It may not be exact because of rounding)

Formulas of Compounds: Empirical Formulas

Definition = the formula of a compound that expresses the smallest whole-number ratio of atoms present

If two solutions are mixed and a solid product is formed, how can you figure out what the solid is?

  • Write the chemical reaction equation
  • Compare the properties of the solid to known substances
  • To obtain the formula of an unknown compound, we use the measured masses of the elements present to determine the formula.

* Remember that a formula tells us the relative numbers of atoms

Example:

A mystery compound contains only the elements carbon, hydrogen, and oxygen and its mass is 0.2015 g. The masses of each element are found to be 0.0806-g of carbon, 0.01353-g of hydrogen, and 0.1074 g of oxygen.

Step 1: Convert to moles

Step 2: Divide by the smallest # of moles of atoms to determine the formula ratio.

What do these numbers tell us?

  • The compound contains the same number of C and O atoms
  • There are twice as many H atoms as C or O atoms.

The substance can be represented by the empirical formula CH2O

Steps for determining Empirical Formulas:

Step 1: Obtain the mass of each element in grams.

Step 2: Determine the number of moles of each atom.

Step 3: Divide by the smallest number of moles to determine the formula ratio. If any number in the ratio is not a whole number, complete step 4.

Step 4: If any numbers are not whole numbers, multiply by the smallest integer that will convert all of them to whole numbers.

Sample Problems:

  1. Determine the empirical formula for a compound composed of 71.65% Cl, 24.27% C, and 4.07% H.
  1. A sample of Nickel with a mass of 0.2636 g is heated and reacts with oxygen in the air to produce 0.3354 g of Nickel oxide.
  • To find the mass of oxygen that reacted with Nickel, subtract the original mass of Nickel from the total product mass of nickel oxide.

Molecular Formulas

Definition: The formula of a compound that indicates the actual number of atoms of each element present.

To determine a compound’s molecular formula, we must know the empirical formula and its molar mass.

Example:

A white powder is analyzed and found to have an empirical formula of P2O5. The compound has a molar mass of 283.88 g. What is the compound’s molecular formula?

1)Determine the empirical formula mass

2 mol of P = 2(30.97) = 61.94 g

5 mol of O = 5(16.00) = 80.00 g

Mass of 1 mol P2O5= 141.94 g

2)To determine the molecular formula, divide the molar mass by the empirical formula mass.

The molecular formula is: (empirical formula)n or (n x empirical formula), SO…

Sample Problems:

  1. A compound with the empirical formula of C2H5O was found to have a molar mass of approximately 90 g. What is the molecular formula for the compound?
  1. Determine the molecular formula of a compound that contains 26.7% P, 12.1% N, and 61.2% Cl and has a molar mass of 580 g/mol.

Molecular Formulas #2

You CAN find the molecular formula using the percent composition and molar mass of a compound.

Steps:

1)Using the mass % and molar mass, determine the mass of each element in 1 mole of the compound

2)Determine the number of moles of each element present in 1 mole of the compound

3)Round numbers to whole integers. These numbers represent the subscripts of the molecular formula.

Example:

Caffeine contains 49.48% Carbon, 5.15% Hydrogen, 28.87% Nitrogen, and 16.49% Oxygen by mass and has a molar mass of 194.2 g/mol. Determine the molecular formula for caffeine.