Gibbs Free Energy Is a Criterion for Spontaneity and Takes Into Account the Entropy Change

Gibbs Free Energy Is a Criterion for Spontaneity and Takes Into Account the Entropy Change

Gibbs Free Energy

Gibbs Free Energy is a criterion for spontaneity and takes into account the entropy change of the surroundings.

The Gibbs Free Energy Function is defined by the equation G = H - TS

For change at constant temperature the equation appears as G = H - T S

Based on G reaction behavior can be predicted accurately.

G negative reaction proceeds spontaneously.
0 reaction is at equilibrium
G positive reaction will not proceed at all

Free energy or reaction can be calculated as follows :

G reaction = G products - G reactants

The value of Gibbs Free Energy for a reaction is based upon its enthalpy and entropy. Both of these factors can have either a negative or positive effect on whether or not a reaction will occur spontaneously or at all. We will even be able to predict at what temperature a nonspontaneous reaction will become spontaneous.

It is called free energy because it is the energy that will be released or freed up to do work.

Consider the following example: H is negative (-ve) and S is positive (+ve)
G = H - TS
= (-) - T(+)

In such a change, G will be negative regardless of the value of the absolute temperature, T (which can only have positive values). Therefore, the change will occur spontaneously at all temperatures.

On the other hand, if a change is endothermic and is accompanied by a decrease in entropy, both factors work against spontaneity.

i.e. H is positive (+ve)
S is negative (-ve)
G = H - TS
= (+) - T(-)

In this case, G will be positive at all temperatures and the change will always be nonspontaneous.

When H and S have the same sign, the temperature becomes critical in determining whether or not an event is spontaneous.

If H and S are both positive,
G = (+) - T(+)

Only at relatively high temperatures will the value of TS be larger than the value of H so that their difference, G, is negative. A familiar example is the melting of ice.

H2O(s) ----> H2O(l)

Here is a change that we know is endothermic and occurs with an increase in entropy. At temperatures above 0oC (when the pressure is 1 atm), ice melts because the TS term is bigger than the H term. At lower temperatures, ice doesn't melt because the smaller value of T gives a smaller value for TS and the difference H-TS, is positive.

SCH4U Gibb's Free Energy Entropy Worksheet

1. / Phosgene, COCl2, was used as a war gas during World War I. It reacts with the moisture in the lungs to produce HCl, which causes the lungs to fill with fluid, leading to death of the victim. COCl2 has a standard entropy, So =284 J/mol K and Ho =-223 kJ/mol. Use this information and appropriate tables to calculate Go for COCl2(g) in kJ/mol at body temperature!
2. / Aluminum oxidizes rather easily, but forms a thin protective coating of Al2O3 that prevents further oxidation of the aluminum beneath. Use the data for Hfo and So to calculate Go for Al2O3(s) in kJ/mol.
3. / Calculate Go in kJ for the following reactions, using the appropriate data tables.
Use Go = Gproducts - Greactants
(a) SO3(g) + H2O(l) ----> H2SO4(l)
(b) 2 NH4Cl(s) + CaO(s) ----> CaCl2(s) + H2O(l) + 2 NH3(g)
(c) CaSO4(s) + 2 HCl(g) ----> CaCl2(s) + H2SO4(l)
(d) C2H4(g) + H2O(l) ----> C2H5OH(l)
(e) Ca(s) + 2 H2SO4(l) ----> CaSO4(s) + SO2(g) + 2 H2O(l)
4. / Calculate the Go in kJ for the following reactions at 100oC using the appropriate data tables.
(a) C2H4(g) + H2(g) ----> C2H6(g)
(b) 5 SO3(g) + 2 NH3(g) -----> 2 NO(g) + 5 SO2(g) + 3 H2O(g)
(c) N2O(g) + NO2(g) ----> 2 NO(g)