Coin Word Problems
Case I: When the total number of coins is give.
a. Ex: The total number of nickels and dimes is 52.
b. Make one of the coins (nickels) = x, the other coins then becomes 52 – x.
Case II: When one variable is given in term of the other.
c. Ex: The number of nickels is twice the number of dimes
d. Make Dimes = x; Nickels is 2x.
General form of the equation when the total amount of money if given.
(number of coins)(value of the coin) + (number of coins)(value of the coins) = total.
1. Suppose you have a coin collection of dimes and quarters containing 46 coins. If you have $6.70, how many of each type of coin do you have?
2. A person has 11 coins consisting of dimes and nickels. If the total amount of money is $0.75, how many of each coin are there?
3. A person has 9 coins consisting of pennies and half dollars. If the total amount of money is $1.56, how many of each coin are there?
4. You have a coin collection of nickels and dimes containing 63 coins. If you have $5.05, how may of each coin do you have?
5. Terry has quarters and dimes and has a total of $6.80. The number of quarters and dimes is 38. How many quarters and dimes does Terry have?
6. Marsha has three times as many one-dollar bills as she does five dollar bills. She has a total of $32. How many of each bill does she have?
7. John received change worth $13. He received 10 more dimes than nickels and 22 more quarters than dimes. How many coins of each did he receive?
8. A certain number of quarters and four times as many pennies is worth $1:45. How many of each coin are there?