Test/GT-3/Set-Q Mittal Sir
III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.
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GT-3
TEST-/12th & 12th Passed
Topic : ORGANIC CHEMISTRY
Date : 15Oct 2014
Max Marks : 100 Time : 55 minutes
Section - I
Rapid Fire - True or False (+1/-0.5)
This section contains 9questions. Each question has 2 choices True OR False for its answer, If correct than mark (T) if incorrect than mark (F).
O
- Boiling point CH3 – C – CH3 < CH3 – CH– CH3 T F
OH
Cl Cl
- Melting point Cl > TF
Cl Cl
- Dipole moment CH3Cl < TF
- Reactivity towards SN2 CH3CH2Br < CH3CH2I TF
- Reactivity towards SN1 CH3 – CH – CH3 < CH3 – CH – CH3 TF
Br Cl
I
- OCH3 + CH3OH TF
O O
- Reactivity towards hydrolysis CH3 – C – O – CH3 > CH3 – C – Cl T F
- Basic nature CH3CH2NH2 < CH3NHTF
- pKa value TF
CH2Cl COOH < CHCl2COOH
Section - II
Single Correct Answer Type(+3/0)
This section contains 12 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONLY ONE is correct.
- Volume of CH4 evolved at S.T.P when 1 mol of H – C C – CH2 – CH – CH2 OH
is treated with excess of CH3MgBr OH
(a) 22.4 lit(b) 44.8 lit(c) 67.2 lit(d) 89.6 lit
- COOH CH2OH
Reagent can be used for this process is –
NO2 NO2
(a) LiAlH4, H2O(b) NaBH4, H2O(c) B2H6, H2O(d) H2/Ni CH3
- The most stable among the following is
NO2 CH3 OCH3
(a) (b) Cl(c)(d)
H
Cl H Cl H Cl H
O
- Which of the following is least stable resonating structure of CH2 = CH – CH = CH – C – H
O O
(a) CH2 – CH – CH = CH – C – H(b) CH2 = CH – CH – CH – C – H
O O
(c) CH2 – CH = CH – CH = C – H(d) CH2 = CH – CH = CH – C – H
- CH3 – CH = CH2
Intermediate formed in above reaction is
(a) CH3 – CH – CH2(b) CH3 – CH – CH2(c) CH3 – CH – CH2(d) CH3 – CH – CH2
Cl NO Cl NO
- OH
COOH Product is
O OH O
(a) COOH(b) COOH(c)(d)
- Which of the following can be dehydrated most readily
(a) -Hydroxy propanoic acid(b) -Hydroxy propanal
(c) -Hydroxy-propyl propanoate (d) -Hydroxy propanal
CH3 – C ––– C – CH3 Product is –
OH OH
O O
(a) CH3 – C –– C (b) CH3 – C –– C – CH3
CH3
O CH3 O
(c) C–– C – CH3(d) CH3 – C –– C
CH3
- The convert propene into 1-Nitropropane the reagent required is/are –
(a) HBr, AgNO2 (b) HBr, NaNO2 (c) HBr; Peroxide, AgNO2(d) HBr ; Peroxide, NaNO2
- Maleic acid when treated with alkaline KMnO4 the product formed is –
(a) Meso tartaric acid(b) Racemic mixture of tartaric acid
(c) R,R Tartaric acid(d) S,S Tartaric acid
- An organic compound ‘A’ having molecular formula C3H6O2 does not give effervescence when treated with NaHCO3. Compound ‘A’ when treated with CH3MgBr followed by acidic hydrolysis it give two alcohols ‘B’ & ‘C’ both give yellow precipitate on treatement with I2 and aqueous alkali. Compound ‘A’ can be
(a) Propanoic acid (b) Methyl ehtanoate (c) Ethyl methanoate (d) -Hydroxy propanone
CH3
- CH3 – CH2 – C – CH2CH3 Total number of monosubstitution products including
CH3 sterioisomersof this compound are
(a) 3(b) 4(c) 5(d) 6
O
- CH3 – CH – CH2 – N – CH2 – C – N – CH3 the product is
H
NH2
O O
(a) CH3 – CH – CH2 – N – CH2 – C – N – CH3 (b) CH3 – CH – CH2 – N – CH2 – C – NH – CH3
H H Cl
NH3Cl–NH2
O
(c) CH3 – CH – CH2 – N – CH2 – C – NH2 – CH3 Cl– (d) None of these
NH2
- Total number of confirmations of type
H
R HWhere R –H –CH –C2H5 –CHCH3C2H5
possible for the compound CH3 – CH2 – CH – CH2 – CH3
H H CH3
R(a) 1(b) 2(c) 3(d) 4
- Total number of sterioisomers of the compound CH3 – CH = CH – CH(OH)CH3 is/are
(a) 2(b) 1(c) 3(d) 4
- C2H5 C2H5The relation between structure ‘A’ & ‘B’ is –
H OH HO H(a) Enantiomer(b) Diasteriomer
H Br CH3 H(c) Anomers(d) same
CH3 Br
(A) (B)
- Which of the following is insoluble in conc. NaOH
OH CHO COOH OCH3
(a) (b)(c)(d)
Section - III
Multiple Correct Answer Type (+4/-1)
This section contains 6 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONE OR MORE THAN ONE is/are correct.
- In which case(s) the product is racemic mixture
(a) O (b) Et O
Me
OH Me C – H
H
Me Et
(c) H CH2Br (d) Me Br
H Me
Et Et
- In which case(s) the product is meso
Et Me Et
(a)(b)
Me
Me Me Me
(c) (d)
Me
- The correct choice(s) among the following is/are –
(a) Ortho nitro phenol and para nitrophenol can be separated by steam distillation
(b) When aniline is nitrated the yield of meta product is greater than ortho product
(c) CN– is an anbident nucleophile
(d) Nucleophilicity I– < Br– < Cl–
- Among P, Q, R and S the aromatic compound(s) is/are –
Cl
(a) P(b) Q
O
(c) R(d) S
O O
- An organic compound ‘A’ having molecular formula C8H8O reduces Tollen’s reagent but does not give red colour with Fehling solution.
The correct statement(s) possible for ‘A’ is/are
(a) On treatment with concentrated alkali ‘A’ will disproportionate
(b) ‘A’ will give effervescence of CO2 with NaHCO3 solution
(c) On oxidation with alkaline KMnO4 followed by acidification ‘A’ will form product with
molecular formula C8H8O4
(d) For nucleophilic reaction like cyanohydrin formation ‘A’ is less reactive than benzaldehyde
Section - IV
Integer type (+4/0)
This section contains 5 questions. The answer to each of the questions is a single digit integer, ranging from 0 to 9. The appropriate bubbles below the respective question numbers in the ORS have to be darkened. For example, if the correct answer to question numbers X, Y, Z and W (say) are 6, 0, 9 and 2, respectively, then the correct darkening of bubbles will look like the following :
- Total number of isomers possible for molecular formula C6H10.
- Total number of structural isomers possible for compound C5H10O which will give yellow ppt with I2 and aqueous Na2CO3
- Total number of hydrogens present in organic product ‘P’
CHO
A P
Cl
- Total number of isomers of molecular formula C4H6
- Among the following the total number of compounds which can be alkylated using Friedal craft reaction (CH3Cl/Anh AlCl3)
NO2 COOH NH2 CH3 OH
, , , , , ,
III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.
email : , website :
GT-3
TEST - 12th & 12th Passed
Topic : ORGANIC CHEMISTRY
Date : 15 OCT 2014
Max Marks : 100 Time : 55 minutes
Note : Write your name and roll no. above in box before filling the answers.
Section – ISection – II
(Rapid Fire / True or False (+1/-0.5)(Straight Objective Type +3/0)
True False A B C D A B C D
1.10.19.
2.11.20.
3.12.21.
4.13.22.
5.14.23.
6.15.24.
7.16.25.
8.17.26.
9.18.
Section – III Section - IV
(Multiple Correct answer Type +4/-1) (Integer Type +4/0)
A B C D 0 1 2 3 4 5 6 7 8 9
27.32.
28.33.
29.34.
30.35.
31. 36.
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