Directions: Select the Best Answer

H E A T

Quiz

Directions: Select the best answer.

Formula: Calories: H = m x ΔT x c

Specific heat: c = H / (m x ΔT)

Thermal expansion: ΔL = (µ) x (L) x (ΔT)

Thermal transfer: H = ( (k) x (ΔT) x (A) x (Δt) ) / d

Thermal Properties of Selected Materials:

Substance: Specific Heat: Thermal Expansion: Thermal conductivity:

cal/g oC cm/cm oC cal/sec cm oC

Aluminum ...... 0.220 ...... 0.000026 ...... 0.4900

Brass ...... 0.087 ...... 0.000019 ...... 0.2600

Copper ...... 0.091 ...... 0.000017 ...... 0.9200

Glass ...... 0.160 ...... 0.000009 ...... 0.0020

Iron ...... 0.110 ...... 0.000011 ...... 0.2000

Steel ...... 0.000011 ......

Lead ...... 0.030 ...... 0.000029 ...... 0.0830

Water ...... 1.000 ...... 0.001430 ...... 0.0014

Ice ...... 0.500 ...... 0.001326 ...... 0.0040

Wood ...... 0.420 ...... 0.000400 ...... 0.0002

Sand ...... 0.200

1. 04, 1 The transfer of heat by the movement of the heated material is called:

A) conduction

B) temperature

C) radiation

D) convection

E) insulation

2. 04, 1 Heat moves through empty space by a process called:

A) convection

B) radiation

C) temperature

D) conduction

E) insulation

3. 04, 2 Determine the number of calories needed to raise 35 grams of water from a temperature of 24oC to the boiling point.

A) 2660

B) 840

C) 3,500

D) 3,330

E) 22,500

4. 04, 2 Determine the number of calories needed to raise a 65 grams of copper from a temperature of 20oC to 38oC.

A) 266

B) 450

C) 106

D) 245

E) 1,128

5. 04, 3 Calculate the specific heat of an unknown substance, and identify that substance, using the chart provided.

where: Mass = 600 g.

Change in temperature = 105oC.

Heat = 1890

A) Aluminum

B) lead

C) Iron

D) Wood

E) Glass

6. 04, 3 Calculate the specific heat of an unknown substance, and identify that substance, using the chart provided.

where: Mass = 285 g.

Change in temperature = 60oC.

Heat = 7182

A) Brass

B) Aluminum

C) Glass

D) Iron

E) Wood

7. 04, 4 Calculate the thermal expansion of glass in the following case: the temperature changes from 2 oC to 35oC, and L = 350 cm.

A) .1 cm.

B) 4.59 cm.

C) .05 cm.

D) 11.9 cm.

E) 120 cm.

8. 04, 5 Calculate the amount of heat loss, (thermal conductivity), for a copper wall in the following case: the temperature changes from 20oC to 40oC, and:

A = 100 cm. by 50 cm.

Δt = 60 sec.

d = 5.08 cm.

A) 1,086,614 calories

B) 5,293,111 calories

C) 886,000 calories

D) 9,375 calories

E) 90,900 calories