RAJALAKSHMIENGINEERINGCOLLEGE

CHENNAI

DEPARTMENT OF BIOMEDICAL ENGINEERING

LAB MANUAL

DIGITAL IMAGE PROCESSING LAB

BM2406

VII SEMESTER 2008-2012 BATCH

Staff incharge

Kalpana R. Associate professor

Nithya A.N.N., Lecturer

List of Experiments

1. Display of Grayscale Images.

2. Histogram Equalization.

3. Non-linear Filtering.

4. Edge detection using Operators.

5. 2-D DFT and DCT.

6. Filtering in frequency domain.

7. Display of color images.

8. conversion between color spaces.

9. DWT of images.

10. Segmentation using watershed transform.

REFERENCE:

1. Rafael C. Gonzalez, Richard E. Woods, Steven Eddins,' Digital Image Processing

using MATLAB', Pearson Education, Inc., 2004.

LIST OF EQUIPMENTS:

Computer, Software MATLAB

Experiment No.1Display of Gray scale Images.

Aim:

To display the Gray scale images.

Apparatus Required:

Computer,Matlab Software

Syntax

imshow(I)

imshow(I,[low high])

imshow(RGB)

imshow(BW)

imshow(X,map)

imshow(filename)

himage = imshow(...)

imshow(..., param1, val1, param2, val2,...)

Theory:

imshow(I) displays the grayscale image I.

imshow(I,[low high]) displays the grayscale image I, specifying the display range for I in [low high]. The value low (and any value less than low) displays as black; the value high (and any value greater than high) displays as white. Values in between are displayed as intermediate shades of gray, using the default number of gray levels. If you use an empty matrix ([]) for [low high], imshow uses [min(I(:)) max(I(:))]; that is, the minimum value in I is displayed as black, and the maximum value is displayed as white.

imshow(RGB) displays the truecolor image RGB.

imshow(BW) displays the binary image BW. imshow displays pixels with the value 0 (zero) as black and pixels with the value 1 as white.

imshow(X,map) displays the indexed image X with the colormap map. A color map matrix may have any number of rows, but it must have exactly 3 columns. Each row is interpreted as a color, with the first element specifying the intensity of red light, the second green, and the third blue. Color intensity can be specified on the interval 0.0 to 1.0.

imshow(filename) displays the image stored in the graphics file filename. The file must contain an image that can be read by imread or dicomread. imshow calls imread or dicomread to read the image from the file, but does not store the image data in the MATLAB workspace. If the file contains multiple images, imshow displays the first image in the file. The file must be in the current directory or on the MATLAB path.

himage = imshow(...) returns the handle to the image object created by imshow.

imshow(..., param1, val1, param2, val2,...) displays the image, specifying parameters and corresponding values that control various aspects of the image display.

Converting RGB Image into gray scale image & extracting the color Spaces

image1=imread('dse_college.jpg');

image2=rgb2gray (image1);

[r c d]=size (image1);

z=zeros(r,c);

tempr=image1;

tempr(:,:,2)=z;

tempr(:,:,3)=z;

imshow(tempr)

tempg=image1;

tempg(:,:,1)=z;

tempg(:,:,3)=z;

imshow(tempg)

tempb=image1;

tempb(:,:,1)=z;

tempb(:,:,2)=z;

imshow(tempb)

Result:

Thus the gray scale image is displayed.

Experiment No.2Histogram Equalization.

Aim:

To enhance contrast using Histogram Equalization.

Apparatus Required:

Computer,Matlab Software

Syntax

J = histeq(I, hgram)

J = histeq(I, n)

[J, T] = histeq(I,...)

newmap = histeq(X, map, hgram)

newmap = histeq(X, map)

[newmap, T] = histeq(X,...)

Theory

histeq enhances the contrast of images by transforming the values in an intensity image, or the values in the colormap of an indexed image, so that the histogram of the output image approximately matches a specified histogram.

J = histeq(I, hgram) transforms the intensity image I so that the histogram of the output intensity image J with length(hgram) bins approximately matches hgram.

histeq automatically scales hgram so that sum(hgram) = prod(size(I)). The histogram of J will better match hgram when length(hgram) is much smaller than the number of discrete levels in I.

J = histeq(I, n) transforms the intensity image I, returning in J an intensity image with n discrete gray levels. A roughly equal number of pixels is mapped to each of the n levels in J, so that the histogram of J is approximately flat. (The histogram of J is flatter when n is much smaller than the number of discrete levels in I.) The default value for n is 64.

[J, T] = histeq(I,...) returns the grayscale transformation that maps gray levels in the image I to gray levels in J.

newmap = histeq(X, map, hgram) transforms the colormap associated with the indexed image X so that the histogram of the gray component of the indexed image (X,newmap) approximately matches hgram. The histeq function returns the transformed colormap in newmap. length(hgram) must be the same as size(map,1).

newmap = histeq(X, map) transforms the values in the colormap so that the histogram of the gray component of the indexed image X is approximately flat. It returns the transformed colormap in newmap.

[newmap, T] = histeq(X,...) returns the grayscale transformation T that maps the gray component of map to the gray component of newmap.

Examples

Enhance the contrast of an intensity image using histogram equalization.

I = imread('tire.tif');

J = histeq(I);

imshow(I)

figure, imshow(J)

Display a histogram of the original image.

figure; imhist(I,64)

Compare it to a histogram of the processed image.

figure; imhist(J,64)

Algorithm

When you supply a desired histogram hgram, histeq chooses the grayscale transformation T to minimizewhere c0 is the cumulative histogram of A, c1 is the cumulative sum of hgram for all intensities k. This minimization is subject to the constraints that T must be monotonic and c1(T(a)) cannot overshoot c0(a) by more than half the distance between the histogram counts at a. histeq uses the transformation b = T(a) to map the gray levels in X (or the colormap) to their new values.If you do not specify hgram, histeq creates a flat hgram,

hgram = ones(1,n)*prod(size(A))/n;

Result

The histogram equalization is done.

Experiment No.3Edge detection using Operators.

Aim:

To detect the edge of the Gray scale images.

Apparatus Required:

Computer, Matlab Software

Syntax

To demonstrate edge detection

% numbers of colors

sncols=128;

ncols=32;

% get image from MATLAB image

load('trees');

% show original image

figure(1);

showgimg(real(X),sncols);

drawnow;

% construct convolution functions

[m,n] = size(X);

gs = [1 -1]; ge = [];

hs = [1 -1]; he = [];

g = [gs,zeros(1,m-length(gs)-length(ge)),ge];

h = [hs,zeros(1,n-length(hs)-length(he)),he];

% construct convolution matrices as sparse matrices

Y = spcnvmat(g);

Z = spcnvmat(h);

Wg = Y*X;

Wh = X*Z';

% show transformed images

figure(2);

showgimg(Wg,ncols);

drawnow;

figure(3)

showgimg(Wh,ncols);

drawnow;

figure(4)

showgimg(abs(Wg)+abs(Wh),ncols);

drawnow;

Theory

Edges characterize boundaries and are therefore a problem of fundamental importance in image processing. Edges in images are areas with strong intensity contrasts – a jump in intensity from one pixel to the next. Edge detecting an image significantly reduces the amount of data and filters out useless information, while preserving the important structural properties in an image. There are many ways to perform edge detection. However, the majority of different methods may be grouped into two categories, gradient and Laplacian. The gradient method detects the edges by looking for the maximum and minimum in the first derivative of the image. The Laplacian method searches for zero crossings in the second derivative of the image to find edges. An edge has the one-dimensional shape of a ramp and calculating the derivative of the image can highlight its location. Suppose we have the following signal, with an edge shown by the jump in intensity below: The intensity changes thus discovered in each of the channels are then represented by oriented primitives called zero-crossing segments, and evidence is given that this representation is complete. (2) Intensity changes in images arise from surface discontinuities or from reflectance or illumination boundaries, and these all have the property that they are spatially localized. Because of this, the zero-crossing segments from the different channels are not independent, and rules are deduced for combining them into a description of the image. This description is called the raw primal sketch.

Result

The edge detection of the image is done.