Thermodynamics and Electrochemistry

1)  Background info:

Cell Potential Electrical Work and Free Energy

emf = potential difference (V) =

cell potential= the negative sign means that work is done by the system.

Maximum work: Wmax = -qEmax

But to obtain work, electrons must flow, which causes friction. Inevitably, in any real spontaneous process, some energy is wasted.

The relationship between Gibbs free energy and Ecell

q = nF F= Faraday’s constant, 96485 Cmol-1

n = # mol of e-1

The change in free energy, DG, is equal to the maximum amount of work obtained by the process.

Wmax = DG

DG = -q Emax = -nFEmax

DG = -nFE

@ standard conditions: DGo = -nFEo

·  The maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.

·  This provides the experimental means to obtain the value for the change in free energy, DG, for a reaction.

·  The relationship between Gibbs fee energy and the E o cell is summarized by the expression above.

·  This relationship also serves as a bridge between thermodynamics and electrochemistry.

2. Voltage and Spontaneity:

Where F = Faraday constant = 96500 J mol/V

96500 C/mole

n = number of moles of electrons transferred

Eo cell = standard reaction potential, V

Go = standard free energy, kJ/mol

K /
Eocell
/ DGo /
Conclusion
> 1 / Positive / Negative / Spontaneous cell reaction
=1 / 0 / 0 / At equilibrium
< 1 / Negative / Positive / Non-spontaneous cell reaction. Reaction is spontaneous in the reverse direction

Example: Calculate the Gibb’s free energy for the following reaction:

Cu2+ Fe ------> Cu + Fe2+

Cu 2+ + 2e------à Cu Eo = +0.34V

Fe ----à Fe 2+ + 2e- Eo = 0.44V

------

Cu2+ Fe ------> Cu + Fe2+ Eo cell = 0.78 V

DGo = - (2mol e-)(9648 Cmol-1)(0.78 J/C)

D Go = -1.5 x 10 5J

- spontaneous since D Go is negative, and the Eo cell is positive.

3. Dependance of Cell Potential on Concentration.

Given the following cell: Cu/Cu2+//Ce4+/Ce3+

Cu(s) + 2 Ce4+(aq) ----- > Cu2+(aq) + 2 Ce3+(aq) Eocell=+1.36V

·  if the concentration of [Ce4+], Le Chatelier’s principle says that the forward reaction is favoured. So the cell potential would increase.

Nerst Equation:

·  equation used to calculate cell potential’s dependance on concentration for NON STANDARD CONDITIONS.

·  Dependance of the cell potential on concentration results directly from the dependance of the free energy on concentration.

DG = DGo + RT lnQ

DG = -nFE, and DGo = -nFEo

-nFE = - nFEo + RT lnQ

Nerst Equation: E = Eo - lnQ

-R is the gas constant (8.314 J/K mol),

-T the Kelvin temperature,

-n the number of electrons transferred between the species,

-F the Faraday constant,

-Eocell is the voltage generated IF the conditions WERE standard,

-ln represents the natural logarithm

-and Q is the reaction quotient.

Note:

·  At standard state, all concentrations are equal to 1, so E = Eo.

·  At 25o C the equation above becomes: E = Eo - logQ

·  As the concentration of the products increase, the voltage decreases.

·  As the concentration of the reactants increases, the voltage increases.

Example Calculation

If the reaction below is carried out using solutions that are 5M Zn2+ and 0.3M Cu2+ at 298K, what is the actual cell voltage? Zn(s) + Cu2+(aq) è Cu(s) + Zn2+(aq)

Firstly, work out the Eocell assuming standard conditions. Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s)

Zn2+(aq) + 2e- çè Zn(s) Eo = -0.76V

Cu2+(aq) + 2e- çè Cu(s) Eo = +0.34V

Eocell = ER – EL = +0.34 - -0.76 = 1.1V

Then calculate Q. Since zinc and copper metals are solids, they are omitted from Q.

Q = [Zn2+]/[Cu2+] = 5/0.3 = 16.7

Two electrons are transferred between the zinc and copper, so n=2. Plug everything in

E = 1.1V - (0.0257/2) * ln (16.7) = 1.06V

Example Calculation 2 Fe3+ + Sn2+ ----- > 2 Fe2+ + Sn4+

In a galvanic cell, all the products have a concentration of 0.0355M and the reactants are 0.100M. What is the voltage at 25oC.

Eocell = - Eosn + EoFe

= -0.154V + 0.771V

= 0.617V

E=0.617V – (8.314)(298)/(2) (96485) ln (0.0355^2) (0.0355)/(0.100^2)(0.100)

E=0.657V

4.  Voltage and equilibrium:

At equilibrium, E=0 and Q=K

E = Eo - lnQ 0 = Eo - lnK

Therefore, Eo = lnK

·  This equation allows us to calculate the equilibrium constant for a redox reaction.

Electrochemistry and Thermodynamics Summary

Voltage and Spontaneity:

Nerst Equation: E = Eo - lnQ

Voltage and Equilibrium: Eo = lnK

K /
Eocell
/ DGo /
Conclusion
> 1 / Positive / Negative / Spontaneous cell reaction
=1 / 0 / 0 / At equilibrium
< 1 / Negative / Positive / Non-spontaneous cell reaction. Reaction is spontaneous in the reverse direction