1. An estimator is called consistent if its variance and standard deviations consistently remain the same regardless of changes in the sample size.

True

False

2. When determining the sample size n, if the value found for n is 79.2, we would choose to sample 79 observations.

True

False

3. The larger the p-value, the more the chance of rejecting the null hypothesis.

True

False

4. A fastener manufacturing company uses a chi-square goodness of fit test to determine if a population of all lengths of ¼ inch bolts it manufactures is distributed according to a normal distribution. If we reject the null hypothesis, it is reasonable to assume that the population distribution is at least approximately normally distributed.

True

False

5. The chi-square distribution is a continuous probability distribution that is skewed to the left.

True

False

6. The error term in the regression model describes the effects of all factors other than the independent variables on y (response variable).

True

False

7. When constructing a confidence interval for a sample proportion, the t distribution is always appropriate if the sample size is small.

True

False

8. When the level of confidence and sample standard deviation remain the same, a confidence interval for a population mean based on a sample of n=100 will be narrower than a confidence interval for a population mean based on a sample of n=50.

True

False

9. The sampling distribution of the sample mean is always normally distributed according to the Central Limit Theorem.

True

False

10. The error term is the difference between the observed value of the dependent variable and the predicted value of the dependent variable.

True

False

11. We do not need to perform the continuity correction if the population is 20 times or more than the sample size.

True

False

12. For a continuous distribution, Probability of (X greater than or equal to 10) is less than the probability of (X greater 10)

True

False

13. In a regression model the population of potential error terms is assumed to have a t-distribution.

True

False

14. The least squares simple linear regression line minimizes the sum squares of the vertical deviations between the line and the data points.

(Points : 8)

True

False

15. In testing the difference between two means from two independent populations, the sample sizes do not have to be equal to be able to use the Z statistic.

True

False

16. To investigate the rate at which employees with cancer are fired or laid off, a telephone survey was taken of 100 cancer survivors who worked while undergoing treatment. Seven (7) were either fired or laid off due to their illness. Construct a 90% confidence interval for the true percentage of all cancer patients who are fired or laid off due to their illness.

[0.0000 0.2034]

[0.0371 0.1029]

[0.0039 0.1361]

[0.0078 0.1400]

[0.0278 0.1122]

17. The area under the normal curve between z=2 and z=3 is ______the area under the normal curve between z=1 and z=2.

Greater than

Less than

Equal to

Answers 1, 2, or 3 depending on the value of the Mean

Answers 1, 2, or 3 depending on the value of the Standard Deviation

18. For a given multiple regression model with three independent variables, the value of the adjusted multiple coefficient of determination is ______less than R .

Always

Sometimes

Never

Can be greater or less depending on the standard error

19. A new company is in the process of evaluating its customer service. The company offers two types of sales: 1. Internet sales; 2. Store sales. The marketing research manager believes that the Internet sales are more than 10% higher than store sales. The null hypothesis would be:

Pinternet-Pstore>.10

Pinternet-Pstore<.10

Pinternet-Pstore >=.10

Pinternet-Pstore <=.10

Pinternet-Pstore=.10

20. If a population distribution is known to be normal, then it follows that:

The sample Mean must equal the population mean

The sample Mean is skewed for small samples but becomes more and more normal as sample size increases

The sample Standard Deviation must equal the population standard deviation

The Sample Proportion must equal the population Proportion

None of the above

21. One survey conducted by a major leasing company determined that the Lexus is the favorite luxury car for 25% of leases in Atlanta. Suppose a US car manufacturer conducts its own survey in an effort to determine if this figure is correct. Of the 384 leases in Atlanta surveyed, 79 lease a Lexus. Calculate the appropriate test statistic to test the hypotheses.

-2.15

-2.00 (Some would also consider -2.00 as a second correct value)

-0.91

2.00

2.51

22. The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. For premium grade, 14 out of 105 samples failed (they didn't meet ASTM specification and the FTC Octane posting rule). How many samples would be needed to create a 99% confidence interval that is within 0.02 of the true proportion of premium grade fuel-quality failures?

(14/105)(91/105)(2.5758/0.02)2 =

4148

2838

1913

744

54

23. A state education agency designs and administers high school proficiency exams. Historically, time to complete the exam was an average of two hours with a standard deviation of 5 minutes. Recently the format of the exam changed and the claim has been made that the time to complete the exam has changed. A sample of 50 new exam times yielded an average time of 118 minutes. Calculate a 99% confidence interval based on the sample result.

Confidence Interval = ( 118 - 2.576(5.000)/sqrt(50) , 118 + 2.576(5.000)/sqrt(50) ) = ( 116.18 , 119.82 )

[117.61 120.09]

[117.36 119.39]

[116.18 119.82]

[115.67 120.33]

[115.82 120.18]

24. The MPG (Miles per Gallon) for a mid-size car is normally distributed with a mean of 32 and a standard deviation of .8. What is the probability that the MPG for a selected mid-size car would be: More than 33.2?

100P(MPG>33.2) = 100P(Z > (33.2-32)/0.8) =

43.32%

6.68%

93.32%

86.64%

13.36%

25. If we are testing the significance of the independent variable X1 in Regression and we reject the null hypothesis H0: B1=0, we conclude that:

X is significantly related to Y (should be X1 not X)

X1 is not significantly related to Y

X1 is an unimportant independent variable

B1 is significantly related to the dependent variable Y

26. In a manufacturing process, we are interested in measuring the average length of a certain type of bolt. Based on a preliminary sample of 9 bolts, the sample standard deviation is .3 inches. How many bolts should be sampled in order to make us 95% confident that the sample mean bolt length is within .02 inches of the true mean bolt length?

(1.96(0.3)/0.02)2 =

865

80

1470

3989

1197

27. The changing ecology of the swamps in Louisiana has been the subject of much environmental research. One water-quality parameter of concern is the total phosphorous level. Suppose that the EPA makes 15 measurements in one area of the swamp, yielding a mean level of total phosphorus of 12.3 parts per billion (ppb) and a standard deviation of 5.4 ppb. The EPA wants to test whether the data support the conclusion that the mean level is less than 15 ppb. Calculate the appropriate test statistic to test the hypotheses.

Test Statistic = [ 12.3 - 15 ] / [ 5.4/sqrt(15) ]

7.50

1.94

3.88

-1.94

-7.50

28. If the sampled population has a mean 48 and standard deviation 16, then the mean and the standard deviation for the sampling distribution of X-bar (sample mean) for n=64

4 and 4

12 and 4

48 and 2

48 and 1/4

48 and 16

29. When we carry out a chi-square test of independence, as the difference between the respective observed and expected frequencies decrease, the probability of concluding that the row variable is independent of the column variable

Decreases

Increases

May increase or decrease depending on the number of rows and columns

Will be unaffected

30. The mean life of pair of shoes is 40 months with a standard deviation of 8 months. If the life of the shoes is normally distributed, how many pairs of shoes out of one million will need replacement before 36

months?

1,000,000P(Life < 36) = 1,000,000P(Z < (36-40)/8)

500,000

808,500

191,500

308,500

31. A set of final examination grades in a calculus course was found to be normally distributed with a mean of 69 and a standard deviation of 8.

Only 5% of the students taking the test scored higher than what grade?

(Show moderate work)

P(Score > x) = 0.05 = P(Z > (x-69)/8)

x = 69+1.64485(8) = 82.2

32. Consider the following partial computer output for a multiple regression model.

Predictor Coefficient Standard Deviation

Constant 41.225 6.380

X1 1.081 1.353

X2 -18.404 4.547

Analysis of Variance

Source DF SS

Regression 2 2270.11

Error 26 3585.75

What is the number of Observations in the sample?

29

Write the least squares regression (prediction) equation.

Y = 41.225 + 1.081X1 - 18.404X2

Test the usefulness of variable x2 in the model at alpha =.05. Calculate the t statistic and state your conclusions.

Test statistic = -18.404/4.547 = -4.05

t(0.025,26) = -2.056

Conclude X2 is useful at alpha = 0.05.

33. A recent study conducted by the state government attempts to determine whether the voting public supports further increase in cigarette taxes. The opinion poll recently sampled 1500 voting age citizens. 1020 of the sampled citizens were in favor of an increase in cigarette taxes. The state government would like to decide if there is enough evidence to establish whether the proportion of citizens supporting an increase in cigarette taxes is significantly greater than .66 at 5% and 10% significance levels. Indicate which test you are performing;

One-proportion z-test

show the hypotheses,

H0: p ≤ 0.66

Ha: p > 0.66

the test statistic

Test Statistic = ( 0.680 - 0.66 ) / sqrt( 0.66 ( 0.34 )/1500 ) = 1.635

and the critical values

5% critical value = z(0.95) = 1.645

10% critical value = z(0.9) = 1.282

and mention whether one-tailed or two-tailed.

One-tailed

Conclude: Not significantly greater than 0.66 at 5%.

Significantly greater than 0.66 at 10%.

34. (I tried to put all the signs in here… they may not come in properly.. I can maybe send them to you another way?)
Test H0: pi1 – pi2 <=.01, HA : pi1 – pi2 > .01 at alpha =.05 where p1 =.08, p2 =.035, n1 = 200, n2 = 400.

Indicate which test you are performing;

2-proportion z-test

show the test statistic

Standard error of p difference = sqrt[ 0.08(0.92)/200+0.035(0.965)/400 ] = 0.0213

Test Statistic = ( 0.080 - 0.035 - 0.01) / 0.0213 = 1.643

and the critical values

Critical value = z(0.95) = 1.6449

and mention whether one-tailed or two-tailed.

One-tailed

Conclusion: Do not reject H0.
35. An apple juice producer buys all his apples from a conglomerate of apple growers in one northwest state. The amount of juice squeezed from each of these apples is known to be normally distributed with a mean of 2.25 ounces and a standard deviation of 0.15 ounce. Between what two values (in ounces) symmetrically distributed around the population mean will 80% of the apples fall?

xL = 2.25 - 1.282(0.15) = 2.06

xU = 2.25 + 1.282(0.15) = 2.44

Between 2.06 ounces and 2.44 ounces.

36. The weight of a product is normally distributed with a standard deviation of .5 ounces. What should the average weight be if the production manager wants no more than 10% of the products to weigh more than 4.8 ounces?

P(X > 4.8) ≤ 0.10

=P(Z > (4.8-average)/0.5) ≤ 0.10

Average ≤ 4.8-1.282(0.5) = 4.16 ounces

37. An insurance company estimates 35 percent of its claims have errors. The insurance company wants to estimate with 90 percent confidence the proportion of claims with errors. What sample size is needed if they wish to be within 5 percentage points of the actual?

0.35(0.65)(1.6449/0.05)2 = 247

38. A human resource manager is interested in whether absences occur during the week with equal frequency. The manager took a random sample of 100 absences and created the following table:

Monday 28

Tuesday 20

Wednesday 12

Thursday 18

Friday 22

At a significance level of alpha = .05 test the Null that the probabilities of absences are the same for all five days.

[(28-20)2+(20-20)2+(12-20)2+(18-20)2+(22-20)2]/20 = 6.8

χ2 (0.05,4) = 9.488

Conclude the probabilities of absences are equal for all 5 days.

39.

At a recent meeting of educational researchers comparison were made between the type of college freshmen attend and the numbers who drop out. A random sample of freshmen show the following results: (keep two decimals in calculating expected frequencies)

4Yr public 4Yr private 2Yr public 2Yr private

drop out 10 9 15 9

don't drop 26 28 18 27

Use a significance level of .05 and determine if the type of school and the drop out rate are independent.

40.

A small town has a population of 15,000 people. Among these 1,500 regularly visit a popular local bar. A sample of 225 people from those who regularly visit the bar is surveyed for their annual expenditures in the bar. It is found that on average each person who regularly visits the bar spends about $2000 per year in the bar with a standard deviation of $196. Construct a 99 percent confidence interval around the mean annual expenditure in the bar.